在sql查询中为csv / excel报告创建用户的总和/总行数

Question

下面的查询会提取数据以形成“报告”，但它基本上只是由CSR代理分组的数字的行项目。它的作用是准确和正确的，在查询后我将结果保存为CSV。但是，它只给我个人记录，所以我必须把它放到excel中并使用公式来插入一个'Totals'行，它基本上总结了我需要总计的列。

这个SQL查询在php脚本中运行，但我不确定最好的方法来修改任何这个，以便我可以为每个用户总计这些列。它会以某种方式说'这是用户7200的记录结束，因此为用户7200插入总计行，然后转到用户7206的记录'或其他类似的效果。

屏幕截图显示了报告，使用“x”和空格而不是1或0，所以在我的excel公式中，我通常都有一个计数IF“x”变量。我希望我能用这个脚本做类似的事情。查询和截图如下。

这是小提琴：http://sqlfiddle.com/#!9/b6a568/1

小提琴的输出是精确查询的输出，唯一的区别是脚本将其放入csv。

我只是希望有一种方法可以为每个用户创建一个“总计”行，它将加上“x”的数量以及持续时间和保持时间的秒数。

任何有关如何重构这一点的建议都非常感谢。

$result = mysqli_query($conn2,
    "SELECT
          FirstN
          , LastN
        , Extension
        , Recieved
        , Recieved_Known
        , Outbound
        , Outbound_Known
        , Missed_No_VM
        , Missed_VM
        , Missed_Known
        , Calling_Number
        , Called_Number
        , Start_Time
        , End_Time
        , Talk_Time_Seconds
        , Hold_Time_Seconds

        FROM (
          SELECT distinct
           firstn
           , lastn
           , c.extension
           , CASE WHEN LEGTYPE1 = 2 AND ANSWERED = 1 THEN 'x' ELSE '' END AS Recieved
           , case when LEGTYPE1 = 2 and answered = 1 and CALLINGPARTYNO = k.phone_number then 'x' ELSE '' end as Recieved_Known
           , CASE WHEN LEGTYPE1 = 1 then 'x' ELSE '' end  AS Outbound
           , case when  FINALLYCALLEDPARTYNO = kn.long_number then 'x' ELSE '' end as Outbound_Known
           , case when legtype1 = 2 and answered = 0 and finallycalledpartyno  not like '%oice%' then 'x' ELSE '' end as Missed_No_VM
           , case when finallycalledpartyno like '%oice%' then 'x' ELSE '' end as Missed_VM
           , case when legtype1 = 2 and ANSWERED = 0 and CALLINGPARTYNO = k.phone_number then 'x' ELSE '' end as
            Missed_Known
           , a.CALLINGPARTYNO AS Calling_Number
           , a.FINALLYCALLEDPARTYNO AS Called_Number
           , b.starttime as Start_Time
           , b.endtime as End_Time
           , b.duration as Talk_Time_Seconds
           , a.holdtimesecs as Hold_Time_Seconds

          FROM ambition.session a
            INNER JOIN ambition.callsummary b ON a.NOTABLECALLID = b.NOTABLECALLID
            right join jackson_id.users c on a.callingpartyno = c.extension or a.finallycalledpartyno = c.extension
            LEFT JOIN ambition.known_numbers k ON a.callingpartyno = k.phone_number
        left join ambition.known_numbers kn on a.finallycalledpartyno = kn.long_number
                WHERE a.ts >= '2017-12-07' -- curdate()
                and(a.CALLINGPARTYNO in (select extension from ambition.ambition_users) OR a.finallycalledpartyno IN (select extension from ambition.ambition_users))
          ) x
          order by extension;") or die(mysqli_error( $conn2));

好的措施截图：

Answer 1

我不确定你如何唯一地识别用户。我假设扩展名对每个用户都是唯一的。基于此我提出以下查询：

SELECT
          Extension
        , Recieved
        , Recieved_Known
        , Outbound
        , Outbound_Known
        , Missed_No_VM
        , Missed_VM
        , Missed_Known
        , Talk_Time_Seconds
        , Hold_Time_Seconds

      FROM (
          SELECT distinct
           c.extension
           , sum(CASE WHEN LEGTYPE1 = 2 AND ANSWERED = 1 THEN 1 ELSE 0 END) AS Recieved
           , sum(case when LEGTYPE1 = 2 and answered = 1 and CALLINGPARTYNO = k.phone_number then 1 ELSE 0 end) as Recieved_Known
           , sum(CASE WHEN LEGTYPE1 = 1 then 1 ELSE 0 end)  AS Outbound
           , sum(case when  FINALLYCALLEDPARTYNO = kn.long_number then 1 ELSE 0 end) as Outbound_Known
           , sum(case when legtype1 = 2 and answered = 0 and finallycalledpartyno  not like '%oice%' then 1 ELSE 0 end) as Missed_No_VM
           , sum(case when finallycalledpartyno like '%oice%' then 1 ELSE 0 end) as Missed_VM
           , sum(case when legtype1 = 2 and ANSWERED = 0 and CALLINGPARTYNO = k.phone_number then 1 ELSE 0 end) as
            Missed_Known
           , sum(b.duration) as Talk_Time_Seconds
           , sum(a.holdtimesecs) as Hold_Time_Seconds

          FROM session a
        INNER JOIN callsummary b ON a.NOTABLECALLID = b.NOTABLECALLID
        right join users c on a.callingpartyno = c.extension or a.finallycalledpartyno = c.extension
        LEFT JOIN known_numbers k ON a.callingpartyno = k.phone_number
        left join known_numbers kn on a.finallycalledpartyno = kn.long_number
          WHERE a.ts >= '2017-12-07' -- curdate()
          and(a.CALLINGPARTYNO in (select extension from ambition_users) OR a.finallycalledpartyno IN (select extension from ambition_users))
        group by c.extension    
      ) x

          order by extension;

至少上面的查询会给你一些如何解决问题的想法。