代码在没有借用的情况下工作，但我无法借用它

Question

我有一些代码并且它可以工作，但AFAIK借用是专门为避免像split_text方法那样手动传入和传出方法。

fn main() {
    println!("Hello, world!");
    let mut test = String::from("12345");
    let mut obj1 = Object {
        text: test.as_mut_str(),
        next: None,
    };
    for i in 0..5 {
        obj1 = obj1.split_text(4 - i);
        if let Some(obj) = obj1.next.as_ref() {
            println!("{}", obj.text);
        }
    }
}

struct Object<'a> {
    text: &'a mut str,
    next: Option<Box<Object<'a>>>,
}

impl<'a> Object<'a> {
    fn split_text(mut self, count: usize) -> Self {
        let tmp = self.text;
        let (part1, part2) = tmp.split_at_mut(count);
        self.text = part1;
        let obj2 = Object {
            text: part2,
            next: None,
        };
        self.next = Some(Box::new(obj2));
        self
    }
}

（Qazxswpoi）

但我无法弄清楚如何通过借阅检查

Playground

导致错误

impl<'a> Object<'a> {
    fn split_text(&'a mut self, count: usize) {
        let tmp = &mut self.text;
        let (part1, part2) = tmp.split_at_mut(count);
        self.text = part1;
        let obj2 = Object {
            text: part2,
            next: None,
        };
        self.next = Some(Box::new(obj2));
    }
}

（Qazxswpoi）

有没有办法使这个代码工作？

Answer 1

问题是你在

error[E0499]: cannot borrow `obj1` as mutable more than once at a time
  --> src/main.rs:11:9
   |
11 |         obj1.split_text(4 - i);
   |         ^^^^ mutable borrow starts here in previous iteration of loop

error[E0502]: cannot borrow `obj1.next` as immutable because it is also borrowed as mutable
  --> src/main.rs:12:28
   |
11 |         obj1.split_text(4 - i);
   |         ---- mutable borrow occurs here
12 |         if let Some(obj) = obj1.next.as_ref() {
   |                            ^^^^^^^^^
   |                            |
   |                            immutable borrow occurs here
   |                            mutable borrow later used here

error[E0506]: cannot assign to `self.text` because it is borrowed
  --> src/main.rs:27:9
   |
23 | impl <'a> Object<'a> {
   |       -- lifetime `'a` defined here
24 |     fn split_text(&'a mut self, count:usize) {
25 |         let tmp = &mut self.text;
   |                   -------------- borrow of `self.text` occurs here
26 |         let (part1, part2) = tmp.split_at_mut(count);
   |                              ----------------------- argument requires that `self.text` is borrowed for `'a`
27 |         self.text = part1;
   |         ^^^^^^^^^^^^^^^^^ assignment to borrowed `self.text` occurs here

函数中借用Playground可变对象obj1生命周期，直到split_text函数的末尾。

'a

你想为main函数可变地借用它，即不同的（较小的）生命周期 - 你可以忽略或指定另一个 - 比如说

fn main() {
    println!("Hello, world!");
    let mut test = String::from("12345");
    let mut obj1 = Object {                             // 'a start
        text: test.as_mut_str(),
        next: None,
    };
    for i in 0..5 {
        obj1 = obj1.split_text(4 - i);                  // borrow for 'a lifetime,
                                                        // Won't work in next iteration
        if let Some(obj) = obj1.next.as_ref() {         // Won't work
            println!("{}", obj.text);
        }
    }
}                                                       // 'a end

。

split_text

明确的不同生命期版本（仅为完整性）：

'b

此外，只有在需要时才能制作可变的东西。我改变了可变切片并分裂成正常。