如何使开关根据蓝牙的状态自动切换(也必须手动工作)?我需要什么方法?
我有一个简单的开关,可用来手动打开和关闭蓝牙。而且效果很好,但是,如果从另一个应用程序或在手机设置中打开/关闭了蓝牙,则开关当然不会改变。
BluetoothAdapter mBluetAdapter = BluetoothAdapter.getDefaultAdapter();
Switch mySwitch = findViewById(R.id.blueSwc);
mySwitch.setChecked(mBluetAdapter.isEnabled()); //this only works at the beginning
您唯一的问题是,您必须聆听蓝牙状态的变化。为此,您需要一个BroadcastReceiever
来监听蓝牙适配器的状态。您的其余代码与此都可以。
private final BroadcastReceiver mBroadcastReceiver1 = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
final String action = intent.getAction();
if (action.equals(BluetoothAdapter.ACTION_STATE_CHANGED)) {
final int state = intent.getIntExtra(BluetoothAdapter.EXTRA_STATE, BluetoothAdapter.ERROR);
switch(state) {
case BluetoothAdapter.STATE_OFF:
mySwitch.setChecked(false);
break;
case BluetoothAdapter.STATE_TURNING_OFF:
break;
case BluetoothAdapter.STATE_ON:
mySwitch.setChecked(true);
break;
case BluetoothAdapter.STATE_TURNING_ON:
break;
}
}
}
};
像这样注册
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
IntentFilter filter1 = new IntentFilter(BluetoothAdapter.ACTION_STATE_CHANGED);
registerReceiver(mBroadcastReceiver1, filter1);
...
}
并且像这样注销它
@Override
protected void onDestroy() {
super.onDestroy();
unregisterReceiver(mBroadcastReceiver1);
}
摘自this answer,其中有如何使用这种类型的BroadcastReceiver
的非常详细的描述。
希望有帮助。