Scala如何对包含字符串和数字的地图进行排序

Question

我正在尝试通过获取字符串并对字符串中的数字进行排序来对mutable.Map [String，String]进行排序。输入：

"Liz", "Game: 2"
"Philip", "Game: 5"
"Philip", "Game: 0"

输出到这样的东西

"John", "Game: 5"
"Liz", "Game: 2"
"Philip", "Game: 0"

我已经尝试过此https://alvinalexander.com/scala/how-to-sort-map-in-scala-key-value-sortby-sortwith/但它并没有做我想要的排序对不起，我的语法不好

Answer 1

您需要从字符串中获取数字并将其转换为Integer，例如：

val map: Map[String, String] = Map(("Liz", "Game: 11"), ("Philip", "Game: 5"))
val order: ((String, String)) => Integer = { case (_ , p2) => p2.stripPrefix("Game: ").toInt }
map.toSeq
  .sortWith(order(_) > order(_))
  .toList

Answer 2

样本数据：

scala> tmp
res19: scala.collection.mutable.Map[String,String] = Map(Philip -> Game: 0, John -> Game: 5, Liz -> Game: 2)

创建案例类：

case class someclass(name:String,score:Int,keyword:String)

将数据放入List[someClass]：

val listOfScores = tmp.map(each => { 
  val name = each._1
  val keyword = each._2.split(":")(0)
  val score = each._2.split(":")(1).stripPrefix(" ").toInt
  someclass(name,score,keyword)
})

最后排序并获得最终列表：

scala> listOfScores.toList.sortBy(_.score).reverse
res31: List[someclass] = List(someclass(A1,9,Goals), someclass(a2,5,Game), someclass(Liz,2,Game), someclass(John,0,Score), someclass(Philip,0,Game))