如果我从(cursor2.items(100))中删除值100,下面的getting_friends_follwers()
函数将起作用。我的目标是获取这些名称(关注者和朋友)并将其保存在“ amigos.txt”文件中。
问题:名称screen_name
有大量的朋友和关注者,因此,该连接已被Twitter关闭。我考虑过尝试捕获100个名称中的100个(因此在对cursor2的调用中值为100),但是发生以下错误:
builtins.TypeError: '<' not supported between instances of 'User' and 'User'
如何解决?
f = open("amigos.txt","w")
Meu = []
def getting_friends_follwers():
# Get list of followers and following for group of users tweepy
cursor = tweepy.Cursor(api.friends, screen_name="Carlos")
cursor2 = tweepy.Cursor(api.followers, screen_name="Carlos")
## for user in cursor.items():
## print('friend: ' + user.screen_name)
for user in sorted(cursor2.items(100)):###funciona se eu tirar este valor!!!
f.write(str(user.screen_name)+ "\n")
print('follower: ' + user.screen_name)
f.close()
getting_friends_follwers()
您会收到此错误,因为您正在将项目传递给“已排序”功能,该功能正在尝试对那些“用户”对象进行排序,但由于没有有关如何“对”蠕虫用户进行“排序”的说明,因此无法执行此操作对象。
如果删除“已排序”,则该程序可以正常运行。
此外,您在调用函数之前关闭文件。我建议您使用“ with open”语法来确保文件正确关闭。
您可以这样编写代码:
def getting_friends_follwers(file):
# Get list of followers and following for group of users tweepy
cursor = tweepy.Cursor(api.friends, screen_name="Carlos")
cursor2 = tweepy.Cursor(api.followers, screen_name="Carlos")
## for user in cursor.items():
## print('friend: ' + user.screen_name)
for user in cursor2.items(100):###funciona se eu tirar este valor!!!
file.write(str(user.screen_name)+ "\n")
print('follower: ' + user.screen_name)
with open("amigos.txt", "w") as file:
getting_friends_follwers(file)