VBA Transpose with filldown

Question

我想在下面进行数据转置，保持第一列“连接”到值。

        Q1    Q2   Q3
Shop 1  100  90   110
Shop 2  90   110  130

Shop 1   Q1   100
Shop 1   Q2   90
Shop 1   Q3   110
Shop 2   Q1   90
Shop 2   Q2   110
Shop 2   Q3   130

我正在使用以下代码，它适用于最后两列，但我无法执行第一列。请帮忙吗？

Sub test()
Dim r As Range, c As Range, dest As Range

With Worksheets(“Sheet1”)
Set r = Range(.Range(“C2”), .Range(“C2”).End(xlDown))

For Each c in r

‘Sales
Range(c, c.End(xlToRight)).Copy
With Worksheets(“Sheet1”)
Set dest = .Cells(Rows.Count, “O”).End(xlUp).Offset(1, 0)
dest.PasteSpecial Transpose:=True
End With

‘Quarters
Worksheets(“Sheet1”).Range(“C1:E1”).Copy
With Worksheets(“Sheet1”)
Set dest = .Cells(Rows.Count, “N”).End(xlUp).Offset(1, 0)
dest.PasteSpecial Transpose:=True
End With

Next c

End With

End Sub

Answer 1

诀窍是将数据视为一个表格，其顶部是标题行，左侧是标题列。然后对于“内部”表中的每个数据位（即没有标题左侧和顶部的位），您希望从左侧打印单元格，然后打印上面的单元格，然后打印数据

Sub Expand(sourcerange As Range, dest As Range)
'pass this the entire table including headersas sourcerange, a single cell as dest

Dim r As Range
Dim xCol As Long  'left hand column as number
Dim yRow As Long  'top row as number
xCol = sourcerange.Cells(1, 1).Column
yRow = sourcerange.Cells(1, 1).Row
With sourcerange.Parent
For Each r In .Range(sourcerange.Cells(2, 2), .Cells(sourcerange.Rows.Count + yRow - 1, sourcerange.Columns.Count + xCol - 1))
    dest = .Cells(r.Row, xCol)
    dest.Offset(0, 1) = .Cells(yRow, r.Column)
    dest.Offset(0, 2) = r
    Set dest = dest.Offset(1, 0)
Next r
End With
End Sub