如何在Codeigniter框架中输出mysql函数的参数？

Question

我有一个MySQL程序GET_JOB_ID，输出参数是job_id。然后我从codeigniter称呼它

$data = $this->db->query("CALL GET_JOB_ID()");

那么如何从job_id获取输出参数codeigniter？

Answer 1

我得到了答案。

$job_id = 0;
    $this->load->database();   
    $job_data = $this->db->query("CALL GET_JOB_ID(@job_id)");
    $out_param_query = $this->db->query('select @job_id as job_id;'); 
    foreach ($out_param_query->result() as $key) {
        $job_id = $key->job_id;
    }
    $this->db->close();