如何获取重载模板成员函数的指针，获取非模板成员函数的指针

Question

我有以下场景：

class C
{
public:
  template <typename T>
  std::shared_ptr<T> foo();

  std::shared_ptr<SomeClass> foo(std::string_view sw);
};

class DerivedFromC : public C
{
// no logic concerning foo
};

// in my bindings

pybind11::class_<DerivedFromC, ...some options...>(m, "Name")
  .def("foo", pybind11::overload_cast<std::string_view>(&DerivedFromC::foo));

此代码编译时不会出现错误消息：

[build] pythonbind.hpp(51,21): error: no matching function for call to object of type 'const detail::overload_cast_impl<basic_string_view<char, char_traits<char>>>'
[build]    51 |         .def("foo", pybind11::overload_cast<std::string_view>(&DerivedFromC::foo));
[build]       |                     ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
[build] ...\build\vcpkg_installed\x64-windows\include\pybind11/detail/common.h(1106,20): note: candidate template ignored: couldn't infer template argument 'Return'
[build]  1106 |     constexpr auto operator()(Return (*pf)(Args...)) const noexcept -> decltype(pf) {
[build]       |                    ^
[build] ...\build\vcpkg_installed\x64-windows\include\pybind11/detail/common.h(1111,20): note: candidate template ignored: couldn't infer template argument 'Return'
[build]  1111 |     constexpr auto operator()(Return (Class::*pmf)(Args...), std::false_type = {}) const noexcept
[build]       |                    ^
[build] ...\build\vcpkg_installed\x64-windows\include\pybind11/detail/common.h(1117,20): note: candidate function template not viable: requires 2 arguments, but 1 was provided
[build]  1117 |     constexpr auto operator()(Return (Class::*pmf)(Args...) const, std::true_type) const noexcept
[build]       |                    ^          ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

我做错了什么或者有特殊的方法来检索该函数的指针吗？对我来说，感觉

overload_cast

函数应该选择正确的重载，因为模板化函数没有任何参数。

Answer 1

我通过手动

static_cast

-ing 到正确的签名解决了我的问题，如下所示。

pybind11::class_<DerivedFromC, ...some options...>(m, "Name")
  .def("foo", static_cast<std::shared_ptr<SomeClass>(DerivedFromC::*)(std::string_view)>(&DerivedFromC::foo));

但是，这对我来说似乎并不优雅。因此，如果有人有更好（更优雅）的解决方案，就会将此作为答案。