用括号、子括号和空格分割字符串

Question

在Python中，我有以下字符串：

string_example = '11 31 (31 573) ((11 573)<(31 573 [1 0 0])<(11 31))'

我想通过使用空格和“()”作为分隔符拆分字符串来提取列表，而不拆分子括号。所需的列表是：

list_split=['11', '31', '(31 573)', '((11 573)<(31 573 [1 0 0])<(11 31))']

Answer 1

思路：根据空格或括号分割字符串，如果有多个括号，则匹配相同数量的右括号结束分割。

def custom_split(string):
result = []
current = ""
count = 0
for char in string:
    if char == ' ' and count == 0:
        if current:
            result.append(current)
        current = ""
    elif char == '(':
        count += 1
        current += char
    elif char == ')' and count > 0:
        count -= 1
        current += char
        if count == 0:
            result.append(current)
            current = ""
    else:
        current += char

if current:
    result.append(current)

return result

string_example = '11 31 (31 573) ((11 573)<(31 573 [1 0 0])<(11 31))'
list_split = custom_split(string_example)
print(list_split)

此函数逐个字符地迭代输入字符串，并根据空格或括号进行分割。当遇到左括号时，计数器增加，当遇到右括号时，计数器减少。仅当计数器达到零时，当前拆分单元才会结束并添加到结果列表中。