如何将注释水平居中于某个点？

Question

我想采用类似这样的代码来进行散点图注释...

import matplotlib; matplotlib.use('TkAgg')
import matplotlib.pyplot as plt
    
labels = ["Abra", "Kadabra", "Alazkazam", "Mew"]
x_values = [0.3, 0.6, 0.2, 0.4]
y_values = [0.2, 0.2, 0.4, 0.9]

fig = plt.figure(figsize=(5, 5))
plt.axis('off')

renderer = fig.canvas.get_renderer()

for i, label in enumerate(labels):
    plt.scatter(x_values[i], y_values[i])
    text_object = plt.annotate(label, xy=(x_values[i], y_values[i]))

plt.savefig("horizontally_centered_text_annotations.png")

...产生这个情节：

...并使其产生类似以下情节的内容：

我尝试获取文本框周围的窗口范围，获取 x 坐标和宽度，然后为每个注释移动，如下所示：

for i, label in enumerate(labels):
    plt.scatter(x_values[i], y_values[i])
    text_object = plt.annotate(label, xy=(x_values[i], y_values[i]))
    text_window_extent = text_object.get_window_extent(renderer)
    new_x_position = x_values[i] - text_window_extent.width / 2
    text_object.set_position((new_x_position, y_values[i]))
    print "x_value: {}, window_extent_width: {}, new_x_position: {}".format(x_values[i], text_window_extent.width, new_x_position)

但是正如您从打印语句中看到的，宽度太大了：

x_value: 0.3, window_extent_width: 31.5, new_x_position: -15.45
x_value: 0.6, window_extent_width: 56.0, new_x_position: -27.4
x_value: 0.2, window_extent_width: 72.875, new_x_position: -36.2375
x_value: 0.4, window_extent_width: 30.75, new_x_position: -14.975

不确定这是否与坐标系有关...

Answer 1

在

horizontalalignment

调用中使用

ha

（可缩写为

annotate

）选项：

text_object = plt.annotate(label, xy=(x_values[i], y_values[i]), ha='center')