当匹配所有数字时，r for循环

Question

我有一个数据框，每行有7个数字，我想做一个for或while循环告诉我，当一行是一行时。

数据框：

   1st 2nd 3rd 4th 5th 6th 7th
1    5  32  34  38  39  49   8
2   10  20  21  33  40  44  34
3   10  20  26  28  35  48  13
4   14  19  23  36  44  46   7
5    9  24  25  27  36  38  41
6    7  13  14  20  29  32  28
7   11  22  24  28  29  38  20
8    1  11  29  33  36  44  37
9    9  12  25  31  43  44   5
10   1   5   6  31  39  46  44
11   14  19  23  36  44  46   7

期望的输出：

 4   14  19  23  36  44  46   7
11   14  19  23  36  44  46   7

我尝试了代码但错误：lapply（df，function（i）all（df [i，] == df [1：nrow（df），]））

但这不正确。请指教，谢谢。

Answer 1

一个base R选项将是

unique(Filter(Negate(is.null), lapply(seq_len(nrow(df)), function(i) {
       i1 <- rowSums(df[i,][col(df)] == df)== ncol(df)
       if(sum(i1) >1) df[i1,]}) ))
[1]]
#    1st  2nd  3rd  4th  5th  6th  7th
#4    14   19   23   36   44   46    7
#11   14   19   23   36   44   46    7

---

如果我们只对重复的行感兴趣

df[duplicated(df)|duplicated(df, fromLast = TRUE),]
#    1st  2nd  3rd   4th  5th  6th 7th
#4    14   19   23   36   44   46    7
#11   14   19   23   36   44   46    7

Answer 2

使用dplyr::group_by_all()的选项可以非常方便：

library(dplyr)

df %>% group_by_all() %>%
  filter(n()>1)  # n()>1 will make sure to return only rows having duplicates

# # A tibble: 2 x 7
# # Groups: X1st, X2nd, X3rd, X4th, X5th, X6th, X7th [1]
#    X1st  X2nd  X3rd  X4th  X5th  X6th  X7th
#   <int> <int> <int> <int> <int> <int> <int>
# 1    14    19    23    36    44    46     7
# 2    14    19    23    36    44    46     7

数据：

df <- read.table(text = 
"1st 2nd 3rd 4th 5th 6th 7th
1    5  32  34  38  39  49   8
2   10  20  21  33  40  44  34
3   10  20  26  28  35  48  13
4   14  19  23  36  44  46   7
5    9  24  25  27  36  38  41
6    7  13  14  20  29  32  28
7   11  22  24  28  29  38  20
8    1  11  29  33  36  44  37
9    9  12  25  31  43  44   5
10   1   5   6  31  39  46  44
11   14  19  23  36  44  46   7",
header = TRUE)