我想要支持找到2个不同商店中每个产品的总数量,你可以通过使用Php看到下面的两个表。
我试过的这段代码不起作用,但是它让我得到了你在第二个输出表上看到的唯一的Product,但不是每个商店的总数
<table class="table" id="manageStockStatus">
<thead>
<tr>
<th>Product Name</th>
<th>Qty-office</th>
<th>Qty-Yard</th>
<th>T-Qyt</th>
<th>Size/Type</th>
</tr>
<?php
$sql = "SELECT SUM(quantity) AS Tq, (SELECT product_name
from product where stock.product_id=product_id) as pname FROM `stock` GROUP BY product_id ";
$result = $connect->query($sql);
while($row = $result->fetch_array()) {
$Productname=$row['pname'];
$Tqnty=$row['Tq'];
// $Tqnty=$row['Tq'];
// $office=$row[];
// $yard=$row['yard'];
?>
</thead>
<td><?php echo $Productname;?> </td>
<td><!-- <?php echo $office;?> --></td>
<td><!-- <?php echo $yard;?> --></td>
<td><span class="badge"><?php echo $Tqnty; ?></span></td>
<td></td>
</tr>
<?php }?>
</table>
<!-- /table -->
</div> <!-- /panel-body -->
</div> <!-- /panel -->
</div> <!-- /col-md-12 -->
尝试使用左JOIN并执行group by stock.product_id,store
:
SELECT stock.product_id as id,product_name as pname,store,SUM(quantity) AS Tq
FROM `stock` left join product on stock.product_id=product.product_id
group by stock.product_id,store
这样,在你的while循环中你可以:
while($row = $result->fetch_array()) {
$Productname=$row['pname'];
$Tqnty=$row['Tq'];
$office=$row['store'];
?>
编辑
然后您可以像这样使用CASE:
SELECT stock.product_id as id,product.product_name as pname,
sum(case
when store=1 then quantity
else 0
end) as office,
sum(case
when store=2 then quantity
else 0
end) as yard
FROM `stock` left join product on stock.product_id=product.product_id
group by stock.product_id,product.pname
这样,在你的while循环中你可以:
while($row = $result->fetch_array()) {
$Productname=$row['pname'];
$yard=$row['yard'];
$office=$row['office'];
$Tqnty=$office+$yard;
?>