将包含双单元格的表格从 Excel 传输到 pdf

Question

这是脚本本身：

def merge_cells(section):
    merged_section = [section[0], section[1]]  # Сохраняем заголовки
    for i in range(2, len(section), 2):
        if i + 1 < len(section):
            main_row = section[i]
            secondary_row = section[i + 1]
            merged_row = []
            for j in range(len(main_row)):
                if j >= 5 and secondary_row[j] == '':
                    merged_row.append(main_row[j])
                else:
                    merged_row.append(f"{main_row[j]}\n{secondary_row[j]}".strip())
            merged_section.append(merged_row)
    return merged_section

但是它合并了第 1 列到第 12 列的单元格，而我需要合并 PDF 中第 6 列到第 11 列的单元格。

这是列表本身：

section = [
    ['DO 33-48(=24V) signal distribution', '', '', '', '', '', '', '', '', '', ''],
    ['Cable number', 'Wire number', 'Terminal/device number', 'Terminal number', 'Circuit', 'Matching device', 'Parameter type', 'Signal name', 'Tag', 'Logical channel number', 'Module number Channel number', 'Note'],
    ['', '', '3XT6', '1', '3. 6.1', '24V relay', 'SC', 'Enable', 'B1-10-1_ND_On', 'DO:33', 'A20:TU1', ''],
    ['', '', '3XT6', '2', '3.6.2', '', '', '', '', '', ''],
    ['', '', '3XT6', '3', '3. 6.3', '24V relay', 'SC', 'Disable', 'B1-10-1_ND_Off', 'DO:34', 'A20:TU2', ''],
    ['', '', '3XT6', '4', '3.6.4', '', '', '', '', '', ''],
    ['', '', '3XT6', '5', '3. 6.5', '24V relay', 'SC', 'Enable', 'B1-31_ND_On', 'DO:35', 'A20:TU3', ''],
    ['', '', '3XT6', '6', '3.6.6', '', '', '', '', '', ''],
    ['', '', '3XT6', '7', '3.6. 7', '24V relay', 'SC', 'Disable', 'B1-31_ND_Off', 'DO:36', 'A20:TU4', ''],
    ['', '', '3XT6', '8', '3.6. 8', '', '', '', '', '', ''],
    ['', '', '3XT6', '9', '3.6.9', '24V relay', 'SC', 'On', 'B1-13 ND On', 'DO:37', 'A20:TU5', ''],
    ['', '', '3XT6', '10', '3. 6.10', '', '', '', '', '', ''],
    ['', '', '3XT6', '11', '3.6.11', '24V Relay', 'SC', 'Off', 'B1-13 ND Off', 'DO:38', 'A20:TU6', ''],
    ['', '', '3XT6', '12', '3.6. 12', '', '', '', '', '', ''],
    ['', '', '3XT6', '13', '3.6. 13', '24V relay', 'SC', 'Enable', 'B2-10-2_ND_On', 'DO:39', 'A20:TU7', ''],
    ['', '', '3XT6', '14', '3.6.14', '', '', '', '', '', '']
]

尝试了不同的选择，但没有任何效果。

Answer 1

而不是做这样的事情

if j >= 5 and secondary_row[j] == '':
    # Skip Merging
else:
    # Perform the merge

你想像这样改变一切

if j >= 5 and secondary_row[j] == '':
    # Perform the merge here instead
else:
    # Skip Merging

你的情况刚刚发生了一些逆转。就这样。或者，另一种解决方案是保持现状并将您的条件更改为

if j <= 5 or secondary_row[j] == '':

现在，不再需要两个条件都为真才能跳过合并，而是任一条件都为真即可。对于前 5 列，第一个条件始终为真，我们跳过合并。然后，这取决于

secondary_row[j]

是否为空字符串。