Delayed Job将每个请求两次插入后端？

Question

我有一个Rails 5应用程序，其中利用延迟的作业从外部API提取数据并将其保存在数据库存储中，

但是，当我从API发出要进行播种的请求时，它在同一个种子请求中排队两次，而不是处理一次。

根据初步观察，我确实看到两个记录的处理程序与另一个完全不同。下面发布的是我尝试过的代码片段。

需要了解为什么会发生这种情况。寻求任何帮助将不胜感激。预先感谢。

控制器代码

class MovieController < ApplicationController

  def new_movie_seed_request
    @languages = Language.all.by_lang_name
    @movie = Movie.new
  end

  def seed_request_for_movie
    @movie_title = params["mov_title"]
    @movie_language = params["mov_language"]
    if params.present? && params["mov_title"].present? && params["mov_language"].present?
      Delayed::Job.enqueue SeedMovieViaTmdbJob.new(params["mov_title"], params["mov_language"])
      flash.now[:success] = 'Request for seeding has been submitted successfully'
    else
      flash[:danger] = 'Please enter valid movie title and movie language in order to proceed with the seeding request'
      redirect_to action: "new_movie_seed_request"
    end
  end

end

将请求排队后的延迟的作业表记录。

INSERT INTO "delayed_jobs" ("handler", "run_at", "queue", "created_at", "updated_at") VALUES ($1, $2, $3, $4, $5) RETURNING "id"  [["handler", "--- !ruby/object:ActiveJob::QueueAdapters::DelayedJobAdapter::JobWrapper\njob_data:\n  job_class: SeedMovieViaTmdbJob\n  job_id: b21ae8e7-65ec-4960-b697-d6f056c275da\n  provider_job_id: \n  queue_name: default\n  priority: 0\n  arguments:\n  - Gully Boy\n  - hi\n  executions: 0\n  locale: en\n"], ["run_at", "2019-03-22 09:20:41.852410"], ["queue", "default"], ["created_at", "2019-03-22 09:20:41.852566"], ["updated_at", "2019-03-22 09:20:41.852566"]]

INSERT INTO "delayed_jobs" ("handler", "run_at", "queue", "created_at", "updated_at") VALUES ($1, $2, $3, $4, $5) RETURNING "id"  [["handler", "--- !ruby/object:SeedMovieViaTmdbJob\narguments:\n- Gully Boy\n- hi\njob_id: b21ae8e7-65ec-4960-b697-d6f056c275da\nqueue_name: default\npriority: \nexecutions: 0\n"], ["run_at", "2019-03-22 09:20:41.877060"], ["queue", "default"], ["created_at", "2019-03-22 09:20:41.877122"], ["updated_at", "2019-03-22 09:20:41.877122"]]

注意已创建的两个记录的处理程序属性中的更改。

Answer 1

啊哈！