我的代码在 PHP 中无法正常分页,有什么建议吗?

问题描述 投票:0回答:1

我是 PHP 初学者。 我想将我的 mysql 数据库内容从表显示到主首页显示为数据库表中项目数量的分页(有限制)。我的代码显示精确分页的格式,并在第一页中绘制项目(如:http://www.swaminarayantravel.com/category.php?sc=Trekking),但问题是,当我尝试去从下面分页的第 2 页,它转到错误页面。 我的代码是:

<?php

//get the function
include_once ('function.php');
include_once ('includes/connect.php');

    $page = (int) (!isset($_GET["page"]) ? 1 : $_GET["page"]);
    $limit = 4;
    $startpoint = ($page * $limit) - $limit;
    
    //to make pagination
  $sql = "category where category.category='$selcat'";
  ?>
<div class="records round">


  <ul class="homelist">
<?php
                          
        //show records
 $query = mysql_query("SELECT * FROM {$sql} LIMIT {$startpoint} , {$limit}");
echo "<table>
<tr></tr>";
        
        while ($row = mysql_fetch_assoc($query)) {   ?>
<?php echo' <li > <img src="images/subcat/'.$row['file'] .'" height="100" width="100" alt="'.$row['subcategory'] .'"/> 
 <a class="title">'; 
$subcategory= $row["subcategory"];
                        echo "$subcategory"; 
echo'</a>
      <p align="justify">'; 
$detail= $row["subcat_detail"];
                        echo "$detail"; 
                        echo ' </p> '; ?> 
 <?php   }   ?> 
</table></div>
<?php   echo pagination($sql,$limit,$page);  ?>

function.php页面包含以下代码:

<?php



function pagination($query, $per_page = 10,$page = 1, $url ='?'){        
    $query = "SELECT COUNT(*) as `num` FROM {$query}";
    $row = mysql_fetch_array(mysql_query($query));
    $total = $row['num'];
    $adjacents = "2"; 

    $page = ($page == 0 ? 1 : $page);  
    $start = ($page - 1) * $per_page;                               
    
    $prev = $page - 1;                          
    $next = $page + 1;
    $lastpage = ceil($total/$per_page);
    $lpm1 = $lastpage - 1;
    
    $pagination = "";
    if($lastpage > 1)
    {   
        $pagination .= "<ul class='pagination'>";
                $pagination .= "<li class='details'>Page $page of $lastpage</li>";
        if ($lastpage < 7 + ($adjacents * 2))
        {   
            for ($counter = 1; $counter <= $lastpage; $counter++)
            {
                if ($counter == $page)
                    $pagination.= "<li><a class='current'>$counter</a></li>";
                else
                    $pagination.= "<li><a href='{$url}page=$counter'>$counter</a></li>";                    
            }
        }
        elseif($lastpage > 5 + ($adjacents * 2))
        {
            if($page < 1 + ($adjacents * 2))        
            {
                for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<li><a class='current'>$counter</a></li>";
                    else
                        $pagination.= "<li><a href='{$url}page=$counter'>$counter</a></li>";                    
                }
                $pagination.= "<li class='dot'>...</li>";
                $pagination.= "<li><a href='{$url}page=$lpm1'>$lpm1</a></li>";
                $pagination.= "<li><a href='{$url}page=$lastpage'>$lastpage</a></li>";      
            }
            elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
            {
                $pagination.= "<li><a href='{$url}page=1'>1</a></li>";
                $pagination.= "<li><a href='{$url}page=2'>2</a></li>";
                $pagination.= "<li class='dot'>...</li>";
                for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<li><a class='current'>$counter</a></li>";
                    else
                        $pagination.= "<li><a href='{$url}page=$counter'>$counter</a></li>";                    
                }
                $pagination.= "<li class='dot'>..</li>";
                $pagination.= "<li><a href='{$url}page=$lpm1'>$lpm1</a></li>";
                $pagination.= "<li><a href='{$url}page=$lastpage'>$lastpage</a></li>";      
            }
            else
            {
                $pagination.= "<li><a href='{$url}page=1'>1</a></li>";
                $pagination.= "<li><a href='{$url}page=2'>2</a></li>";
                $pagination.= "<li class='dot'>..</li>";
                for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
                {
                    if ($counter == $page)
                        $pagination.= "<li><a class='current'>$counter</a></li>";
                    else
                        $pagination.= "<li><a href='{$url}page=$counter'>$counter</a></li>";                    
                }
            }
        }
        
        if ($page < $counter - 1){ 
            $pagination.= "<li><a href='{$url}page=$next'>Next</a></li>";
            $pagination.= "<li><a href='{$url}page=$lastpage'>Last</a></li>";
        }else{
            $pagination.= "<li><a class='current'>Next</a></li>";
            $pagination.= "<li><a class='current'>Last</a></li>";
        }
        $pagination.= "</ul>\n";        
    }


    return $pagination;
} 
?>
php pagination
1个回答
1
投票

您的代码很完美,但您忘记在请求 URL 中添加“sc=Trekking”。 因此,在您的代码中,“$selcat”可能会变为空,并且 sql 查询不会返回任何内容。

请尝试这个: http://www.swaminarayantravel.com/category.php?sc=Trekking&page=2

也许你应该修改“分页”功能。

你的网站很棒。 我记得我在尼泊尔的旅行。

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