如何使on_message函数在Tornado WebSocketClient中异步工作?
我想我需要等待on_message函数,但我不知道如何。
或者说,在我尝试实现异步WebSocketClient的方式上是否存在根本性的误区?
import tornado.websocket
from tornado.queues import Queue
from tornado import gen
import json
q = Queue()
class WebsocketClient():
def __init__(self, url, connections):
self.url = url
self.connections = connections
print("CLIENT started")
print("CLIENT initial connections: ", len(self.connections))
async def send_message(self):
async for message in q:
try:
msg = json.loads(message)
print(message)
await gen.sleep(0.001)
finally:
q.task_done()
async def update_connections(self, connections):
self.connections = connections
print("CLIENT updated connections: ", len(self.connections))
async def on_message(self, message):
await q.put(message)
await gen.sleep(0.001)
async def connect(self):
client = await tornado.websocket.websocket_connect(url=self.url, on_message_callback=self.on_message)
RuntimeWarning: coroutine 'WebsocketClient.on_message' was never awaited
self._on_message_callback(message)
RuntimeWarning: Enable tracemalloc to get the object allocation traceback
on_message_callback
应该是一个常规函数,而不是一个coroutine。而且它是为了在旧式代码中使用,当时人们使用回调而不是coroutine。
对于新的async风格的代码,你不需要这个回调。你可以直接这样做。
async def connect(self):
client = await tornado.websocket.websocket_connect(url=self.url)
while True:
message = await client.read_message()
if message is None:
# None message means the connection was closed
break
print("Message received:", message)
await q.put(message)
await gen.sleep(0.001)