假设我有一些带有一些简单函数指针的简单类,如下所示:
class ClassWithFuncPointer
{
public:
inline void firstFunction() { /* do something */ };
inline void secondFunction() { /* do something */ };
// MY FUNCTION POINTER
void (ClassWithFuncPointer::*funcPointer) ();
// AND I CAN DEFINE IT BY DEFAULT IN CONSTRUCTOR LIKE THAT:
ClassWithFuncPointer()
{
funcPointer = &ClassWithFuncPointer::firstFunction;
}
// AND NOW I CAN USE MY FUNCTION POINTER INSIDE OF ClassWithFuncPointer, LIKE THAT:
void useFunctionPointer()
{
(this->*funcPointer )();
}
}
所以这里(this->*funcPointer )();
做的工作。
但我无法弄清楚如何使用其他类的funcPointer
,我的意思是这样的:
class otherClass
{
otherClass(){};
ClassWithFuncPointer instanceOfClassWithFuncPointer;
}
现在我如何在funcPointer
成员的otherClass
中使用instanceOfClassWithFuncPointer
。有可能吗?
我尝试了很多变种:
(this->*instanceOfClassWithFuncPointer.funcPointer)();
要么
(instanceOfClassWithFuncPointer.*funcPointer)();
要么
( (&instanceOfClassWithFuncPointer)->*funcPointer )();
要不就
instanceOfClassWithFuncPointer.funcPointer();
但总是得到错误。我无法弄清楚。
那么(C ++ 11或更新版本)如下?
auto fp = instanceOfClassWithFuncPointer.funcPointer;
(instanceOfClassWithFuncPointer.*fp)();
或者(兼容C ++ 98,可能使用更短的变量名)?
(instanceOfClassWithFuncPointer.*instanceOfClassWithFuncPointer.funcPointer)();
以下是一个完整的工作示例
#include <iostream>
struct ClassWithFuncPointer
{
public:
inline void firstFunction ()
{ std::cout << "cwfp::firstFunction()" << std::endl; }
inline void secondFunction ()
{ std::cout << "cwfp::secondFunction()" << std::endl; }
void (ClassWithFuncPointer::*funcPointer) ();
ClassWithFuncPointer()
{ funcPointer = &ClassWithFuncPointer::firstFunction; }
void useFunctionPointer()
{ (this->*funcPointer )(); }
};
class otherClass
{
public:
otherClass ()
{ }
ClassWithFuncPointer instanceOfClassWithFuncPointer;
void foo ()
{
auto fp = instanceOfClassWithFuncPointer.funcPointer;
(instanceOfClassWithFuncPointer.*fp)();
}
};
int main ()
{
otherClass oc;
oc.foo();
}