根据字符串将句子中的单词提取到数组中

Question

我正在寻找最有效的解决方案，它将使我能够构建一个字符串模板，以从使用模板结构的句子中提取单词和短语。

假设我的string如下：

$template = '%% is %% because %%.';

现在，假设我有一个字符串数组：

$strings = [
    'Cheese is the best thing because it is great on chips.',
    'My brother is my best friend because he\'s always been there.', 
    'Listen! StackOverflow is how I am still employed because I am not afraid to ask for help.',
    'Derp... Why is it that I can\'t do this easily? Maybe it is because I need more practice.'
];

我需要可以提取%%通配符在$template中位置的文本的逻辑，以便$strings数组可用于产生以下内容：

$template = '%% is %% because %%.';
$result = [
    ['Cheese','the best thing','it is great on chips.'],
    ['My brother','my best friend','he\'s always been there.'], 
    ['Listen! StackOverflow','how I am still employed','I am not afraid to ask for help.'],
    ['Derp... Why', 'it that I can\'t do this easily? Maybe it is','I need more practice.']
];

注：对物理单词/字母使用“爆炸”不是一个好选择，因为某些单词可能多次出现，而我们只想针对此类事件中的第一个出现。

Answer 1

您可以使用正则表达式作为模板：

$template = '(.+?) is (.+?) because (.+?)';

foreach($strings as $string) {
    preg_match("/$template/", $string, $matches);
    $result[] = [$matches[1], $matches[2], $matches[3]];
    //or
    //$result[] = array_slice($matches, 1);
}

如果没有匹配项，或者只有1个或2个等，您要添加一些错误检查。

如果由于某种原因需要特定的模板名称，则：

$template = '%% is %% because %%.';
$template = str_replace('%%', '(.+?)', $template);