使用替换值的平面数组替换二维数组中的列值

Question

我有一个这种格式的二维数组：

$oldArr = [
    0 => [
        "color" => "red",
        "shape" => "circle",
        "size" => "small",
    ],
    1 => [
        "color" => "green",
        "shape" => "square",
        "size" => "large",
    ],
    2 => [
        "color" => "yellow",
        "shape" => "triangle",
        "size" => "large",
    ],
];

以及这种格式的一维数组：

$newVals = [
    0 => "large",
    1 => "large",
    2 => "small",
];

我正在尝试使用

str_replace()

遍历

"size"

中的每个

$oldArr

值，并将其替换为

$newVals

中与其位置匹配的值。由于这些数组将始终具有相同数量的顶级键值对，因此我基本上是在尝试采用

$newVals

并将其映射到每个

$oldArr["size"]

值。最后的结果应该是

$newArr = [
    0 => [
        "color" => "red",
        "shape" => "circle",
        "size" => "large",
    ],
    1 => [
        "color" => "green",
        "shape" => "square",
        "size" => "large",
    ],
    2 => [
        "color" => "yellow",
        "shape" => "triangle",
        "size" => "small",
    ],
];

任何人都可以推荐最好的方法吗？我在 foreach 循环中尝试了

str_replace

，但没有成功：

foreach($oldArr as $entity):

    str_replace($entity['size'], $newVals, $entity);

endforeach;

Answer 1

您可以使用

array_map()

并一次循环遍历两个数组，而不是使用原始数组的大小值，您只需使用新数组，例如

$result = array_map(function($old, $new){
    return ["color" => $old["color"], "shape" => $old["shape"], "size" => $new];
}, $oldArr, $newVals);

Answer 2

您可以使用此代码：

<?php

$oldArr = [
    0 => [
        "color" => "red",
        "shape" => "circle",
        "size" => "small",
    ],
    1 => [
        "color" => "green",
        "shape" => "square",
        "size" => "large",
    ],
    2 => [
        "color" => "yellow",
        "shape" => "triangle",
        "size" => "large",
    ],
];


$newVals = [
    0 => "large",
    1 => "large",
    2 => "small",
];

$newArr = array();
foreach($oldArr as $key => $entity){
    $newEntity = $entity;
    $newEntity['size'] = $newVals[$key];
    $newArr[$key] = $newEntity;
}

var_dump($newArr);