我创建了一个函数,它返回给定特定公司名称的URL列表。我想知道搜索这个网址列表,并找到有关该公司是否归其他公司所有的信息。
示例:公司“Marketo”被Adobe收购。
我想回头是否有一家公司被收购,以及由谁收购。
这是我到目前为止:
import requests
from googlesearch import search
from bs4 import BeautifulSoup as BS
def get_url(company_name):
url_list = []
for url in search(company_name, stop=10):
url_list.append(url)
return url_list
test1 = get_url('Marketo')
print(test1[7])
r = requests.get(test1[7])
html = r.text
soup = BS(html, 'lxml')
stuff = soup.find_all('a')
print(stuff)
我是网络抓取的新手,我不知道如何真正搜索每个URL(假设我可以)并找到我寻求的信息。
test1的值如下:
['https://www.marketo.com/', 'https://www.marketo.com/software/marketing-automation/', 'https://blog.marketo.com/', 'https://www.marketo.com/software/', 'https://www.marketo.com/company/', 'https://www.marketo.com/solutions/pricing/', 'https://www.marketo.com/solutions/', 'https://en.wikipedia.org/wiki/Marketo', 'https://www.linkedin.com/company/marketo', 'https://www.cmswire.com/digital-marketing/what-is-marketo-a-marketers-guide/']
我想回头是否有一家公司被收购,以及由谁收购
您可以抓住crunchbase网站获取此信息。缺点是您将限制搜索到他们的网站。为了扩展这个,你也可以包括一些其他网站。
import requests
from bs4 import BeautifulSoup
import re
while True:
print()
organization_name=input('Enter organization_name: ').strip().lower()
crunchbase_url='https://www.crunchbase.com/organization/'+organization_name
headers={
'User-Agent':'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/65.0.3325.181 Safari/537.36'
}
r=requests.get(crunchbase_url,headers=headers)
if r.status_code == 404:
print('This organization is not available\n')
else:
soup=BeautifulSoup(r.text,'html.parser')
overview_h2=soup.find('h2',text=re.compile('Overview'))
try:
possible_acquired_by_span=overview_h2.find_next('span',class_='bigValueItemLabelOrData')
if possible_acquired_by_span.text.strip() == 'Acquired by':
acquired_by=possible_acquired_by_span.find_next('span',class_='bigValueItemLabelOrData').text.strip()
else:
acquired_by=False
except Exception as e:
acquired_by=False
# uncomment below line if you want to see the error
# print(e)
if acquired_by:
print('Acquired By: '+acquired_by+'\n')
else:
print('No acquisition information available\n')
again=input('Do You Want To Continue? ').strip().lower()
if again not in ['y','yes']:
break
样本输出:
Enter organization_name: Marketo
Acquired By: Adobe Systems
Do You Want To Continue? y
Enter organization_name: Facebook
No acquisition information available
Do You Want To Continue? y
Enter organization_name: FakeCompany
This organization is not available
Do You Want To Continue? n
笔记
你可以从像Crunchbase这样的网站上找到这些信息。
获得它的步骤如下:
url = 'https://www.example.com/infoaboutmycompany.html'
from selenium import webdriver
from bs4 import BeautifulSoup
driver = webdriver.Firefox()
driver.get(url)
html = driver.page_source
bsobj = BeautifulSoup(html, 'lxml')
res = bsobj.find('div', {'class':'alpha beta gamma'})
res.text.strip()
获得它的代码少于10行。
当然,它可以更改您的列表,从网址列表到公司列表,希望由该网站考虑。对于marketo,它的工作原理。
正如其他答案所提到的,crunchbase是获取此类信息的好地方,但是你需要一个无头浏览器来废弃像Selenium这样的crunchbase
如果你使用ubuntu安装Selenium相当容易。 Selenium需要驱动程序与所选浏览器进行交互。例如,Firefox需要geckodriver
安装geckodriver的最新版本
将驱动程序添加到PATH中,以便其他工具可以找到它或在所有软件都安装的目录中,否则会抛出错误('geckodriver'可执行文件需要在PATH中)
码
from bs4 import BeautifulSoup as BS
from selenium import webdriver
baseurl = "https://www.crunchbase.com/organization/{0}"
query = input('type company name : ').strip().lower()
url = baseurl.format(query)
driver = webdriver.Firefox()
driver.get(url)
html = driver.page_source
soup = BS(html, 'lxml')
acquiredBy = soup.find('div', class_= 'flex-no-grow cb-overflow-ellipsis identifier-label').text
print(acquiredBy)
您还可以使用相同的逻辑获取其他信息,只需检查类/ ID并废弃信息。