Pytorch Python 分布式多重处理：收集/连接不同长度/大小的张量数组

Question

如果多个 GPU 级别上有不同长度的张量数组，则默认的

all_gather

方法不起作用，因为它要求长度相同。

例如，如果您有：

if gpu == 0:
    q = torch.tensor([1.5, 2.3], device=torch.device(gpu))
else:
    q = torch.tensor([5.3], device=torch.device(gpu))

如果我需要按如下方式收集这两个张量数组：

all_q = [torch.tensor([1.5, 2.3], torch.tensor[5.3])

默认的

torch.all_gather

不起作用，因为长度，

2, 1

不同。

Answer 1

由于无法直接使用内置方法进行收集，因此我们需要按照以下步骤编写自定义函数：

1. 使用

   dist.all_gather

   获取所有数组的大小。
2. 找到最大尺寸。
3. 使用零/常量将本地数组填充到最大大小。
4. 使用

   dist.all_gather

   获取所有填充数组。
5. 使用步骤 1 中找到的大小取消添加添加的零/常数。

下面的函数可以做到这一点：

def all_gather(q, ws, device):
    """
    Gathers tensor arrays of different lengths across multiple gpus
    
    Parameters
    ----------
        q : tensor array
        ws : world size
        device : current gpu device
        
    Returns
    -------
        all_q : list of gathered tensor arrays from all the gpus

    """
    local_size = torch.tensor(q.size(), device=device)
    all_sizes = [torch.zeros_like(local_size) for _ in range(ws)]
    dist.all_gather(all_sizes, local_size)
    max_size = max(all_sizes)

    size_diff = max_size.item() - local_size.item()
    if size_diff:
        padding = torch.zeros(size_diff, device=device, dtype=q.dtype)
        q = torch.cat((q, padding))

    all_qs_padded = [torch.zeros_like(q) for _ in range(ws)]
    dist.all_gather(all_qs_padded, q)
    all_qs = []
    for q, size in zip(all_qs_padded, all_sizes):
        all_qs.append(q[:size])
    return all_qs

一旦我们能够执行上述操作，我们就可以根据需要轻松使用

torch.cat

进一步连接成单个数组：

torch.cat(all_q)
[torch.tensor([1.5, 2.3, 5.3])

改编自：github

Answer 2

这是 @omsrisagar 解决方案的扩展，支持任意维张量（不仅是一维张量）。

def all_gather_nd(tensor):
    """
    Gathers tensor arrays of different lengths in a list.
    The length dimension is 0. This supports any number of extra dimensions in the tensors.
    All the other dimensions should be equal between the tensors.

    Args:
        tensor (Tensor): Tensor to be broadcast from current process.

    Returns:
        (Tensor): output list of tensors that can be of different sizes
    """
    world_size = dist.get_world_size()
    local_size = torch.tensor(tensor.size(), device=tensor.device)
    all_sizes = [torch.zeros_like(local_size) for _ in range(world_size)]
    dist.all_gather(all_sizes, local_size)

    max_length = max(size[0] for size in all_sizes)

    length_diff = max_length.item() - local_size[0].item()
    if length_diff:
        pad_size = (length_diff, *tensor.size()[1:])
        padding = torch.zeros(pad_size, device=tensor.device, dtype=tensor.dtype)
        tensor = torch.cat((tensor, padding))

    all_tensors_padded = [torch.zeros_like(tensor) for _ in range(world_size)]
    dist.all_gather(all_tensors_padded, tensor)
    all_tensors = []
    for tensor_, size in zip(all_tensors_padded, all_sizes):
        all_tensors.append(tensor_[:size[0]])
    return all_tensors

请注意，这要求所有张量具有相同的维度数，并且除第一个维度外，所有维度都相等。

Answer 3

可以使用内置方法而无需填充，因为 PyTorch 1.6.0 引入了

all_to_all

:

import torch.distributed as dist
import torch


def all_gather_variable(tensor_list, tensor, group=None, async_op=False):
    rank, world_size = dist.get_rank(), dist.get_world_size()
    shape = torch.as_tensor(tensor.shape)
    shapes = [torch.empty_like(shape) for _ in range(world_size)]
    dist.all_gather(shapes, shape, group=group)
    inputs = [tensor] * world_size
    return dist.all_to_all(tensor_list, inputs, group, async_op)