我想获取当前用户的位置。我试图重构我的代码以获得更好的结果，但我只是在准确性方面保持荒谬的位置，它在900-600米之间。
如何才能获得更好的结果，从而使其达到50米以内的精度？
这是我的代码：
package com.agam.mapslocation;
import android.location.Criteria;
import android.location.Location;
import android.location.LocationListener;
import android.location.LocationManager;
import android.os.Bundle;
import android.app.Activity;
import android.content.Context;
import android.view.Menu;
import android.view.View;
import android.widget.EditText;
public class MapsActivity extends Activity {
private static final int ONE_MINUTE = 1000 * 60 * 1;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_maps);
final LocationManager locationManager = (LocationManager) this
.getSystemService(Context.LOCATION_SERVICE);
final EditText et = (EditText) findViewById(R.id.editText1);
// Define a listener that responds to location updates
LocationListener locationListener = new LocationListener() {
public void onLocationChanged(Location l) {
// Called when a new location is found by the network location
// provider.
Location gps = locationManager
.getLastKnownLocation(LocationManager.GPS_PROVIDER);
Location net = locationManager
.getLastKnownLocation(LocationManager.NETWORK_PROVIDER);
Location bestLocation = null;
bestLocation = isBetterLocation(gps, net);
bestLocation = isBetterLocation(bestLocation, l);
if(bestLocation!=null)
displayLocation(et, bestLocation);
}
public void onStatusChanged(String provider, int status,
Bundle extras) {
}
public void onProviderEnabled(String provider) {
if (provider.equals(LocationManager.GPS_PROVIDER)) {
et.setText("GPS ON!");
}
}
public void onProviderDisabled(String provider) {
}
};
// Register the listener with the Location Manager to receive location
// updates
locationManager.requestLocationUpdates(
LocationManager.NETWORK_PROVIDER, 0, 0, locationListener);
locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0,
0, locationListener);
}
public static void displayLocation(View v, Location l) {
((EditText) v).setText(String.format(
"Long:%s,\nLat:%s,\nAccu:%s,\nTime ago:%s,\nProvider:%s",
l.getLongitude(), l.getLatitude(), l.getAccuracy(),
new java.util.Date().getTime() - l.getTime(), l.getProvider()));
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.activity_maps, menu);
return true;
}
/**
* Determines whether one Location reading is better than the current
* Location fix
*
* @param location
* The new Location that you want to evaluate
* @param currentBestLocation
* The current Location fix, to which you want to compare the new
* one
*/
protected Location isBetterLocation(Location location,
Location currentBestLocation) {
if (currentBestLocation == null) {
// A new location is always better than no location
return location;
}
// Check whether the new location fix is newer or older
long timeDelta = location.getTime() - currentBestLocation.getTime();
boolean isSignificantlyNewer = timeDelta > ONE_MINUTE;
boolean isSignificantlyOlder = timeDelta < -ONE_MINUTE;
boolean isNewer = timeDelta > 0;
// If it's been more than two minutes since the current location, use
// the new location
// because the user has likely moved
if (isSignificantlyNewer) {
return location;
// If the new location is more than two minutes older, it must be
// worse
} else if (isSignificantlyOlder) {
return currentBestLocation;
}
// Check whether the new location fix is more or less accurate
int accuracyDelta = (int) (location.getAccuracy() - currentBestLocation
.getAccuracy());
boolean isLessAccurate = accuracyDelta > 0;
boolean isMoreAccurate = accuracyDelta < 0;
boolean isSignificantlyLessAccurate = accuracyDelta > 200;
// Check if the old and new location are from the same provider
boolean isFromSameProvider = isSameProvider(location.getProvider(),
currentBestLocation.getProvider());
// Determine location quality using a combination of timeliness and
// accuracy
if (isMoreAccurate) {
return location;
} else if (isNewer && !isLessAccurate) {
return location;
} else if (isNewer && !isSignificantlyLessAccurate
&& isFromSameProvider) {
return location;
}
return currentBestLocation;
}
/** Checks whether two providers are the same */
private boolean isSameProvider(String provider1, String provider2) {
if (provider1 == null) {
return provider2 == null;
}
return provider1.equals(provider2);
}
}
注意：我强调静态位置，例如不动，因为它可能有助于答案。
要获得准确的位置，您需要考虑两个因素：
这些将在下面讨论。
码
确保你遵循了Android Developer的指导（谢谢Bill Gary）
但请记住，只有当设备本身具有必要的硬件和配置时，代码才会起作用 - 见下文。
设备
要了解您的位置修复程序出了什么问题，了解设备如何定位本身确实很有帮助。位置是通过几种技术获得的：
当你要求一个位置修复（不包括最后一个，缓存的），一个好的GPS位置提供商实际上看起来不仅仅是GPS：
通常，您可以在Google地图上看到这些效果，例如：当您启动它时，您会看到来自网络提供商的大型大致位置（手机信号塔），几秒钟后它会放大一个具有更高精确度的区域（WiFi） ），最后你可能得到GPS修复。
它始终值得：
编辑
从您获得的基本结果来看，您似乎只有网络提供商的结果。所以，做：
您应该尽快将locationListeners设置为所有可用的位置提供程序并等待。设置监听器要求提供者立即为您提供所有数据（minTime = 0，minDistance = 0）。使用getLastKnownLocation作为第一个位置近似值。在此期间，您将开始从不同的提供商处获取一些位置数据。您应该手动选择最适合您的情况（我猜是最精确的）。尽可能长时间等待（您等待的位置值越多，您可能会获得）。当等待时间结束时，请选择您最好的位置并开始使用它。如果系统能够为您提供更好的价值，您可以继续侦听位置更新并改进位置估算。