mongoose推入阵列无法正常工作

问题描述 投票:1回答:2

我正在使用后端的Nodejs和MongoDB作为数据库创建一个Library Management应用程序。它是一个简单的快速服务器,使用mongoose库。必须发出书籍的客户发送POST请求,并将其记录添加到数据库中。这是我的日志模型:

var Logs = mongoose.model('Logs', {


bookid: {
    type: Number,
    required: true,
    minlength: 1
  },
  status: {
    type: String,
    required: true,
    minlength: 1,
    trim: true
  },
  details: [{
    issuedby: {
      type: String,
      trim: true
    },
    issuedate: {
      type: Date,
    },
    returndate: {
      type: Date
    }
  }]
});  

现在收到POST请求时,我尝试将书籍的“状态”从“可用”更改为“已发布”,并在“详细信息”字段中添加客户记录。这是代码:

app.post('/issueBook', (req,res) => {
  console.log(req.body);
  Logs.findOne({bookid: req.body.bookid}).then((doc) => {
    if(doc.status == "Available"){
      var detail = {};
      detail.issuedby = req.body.issueTo;
      detail.issuedate = new Date();
      Logs.findOneAndUpdate({bookid: req.body.bookid}, {$set: {status:"Issued"}}, {$push: {details:detail}}, {upsert: true}, function(err,doc) {
        if(err) {
          console.log("Couldn't issue");
          res.status(400).send(err);
        } else{
          res.send("OK");
        }
      });
    } else{
      res.send({
        status: "Error",
        reason: "Book already issued !"
      });
    }
  }, (e) => {
    res.send({
      status: "Error",
      reason: "Invalid Book ID !"
    });
  });
});  

发送此P​​OST请求时服务器崩溃。在检查数据库时,我发现“status”字段成功地从“Available”更改为“Issued”,但没有在“details”中插入记录。我的查询有问题吗?请建议更正我的代码。 崩溃时这是错误的片段: 终端错误如下所示:

enter image description here

arrays node.js mongodb mongoose
2个回答
0
投票

Change this code


Logs.findOneAndUpdate({bookid: req.body.bookid}, {$set: {status:"Issued"}}, {$push: {details:detail}}, {upsert: true}, function(err,doc)

To this


Logs.findOneAndUpdate({bookid: req.body.bookid}, {$set: {status:"Issued"}}, {$push: {details:detail}}, {upsert: true}).then((result) => {
  console.log(result)
}.catch((error) => {
  console.log(error)
}

请告诉我console.log(错误)将返回什么,并根据该错误消息,我能够给你一个最终的答案。

Update


您可以尝试以下代码块。此代码将查找带有您将在request.body中提供的ID的日志,状态为Available。如果此查询找到日志,它将在响应中将其发回。如果没有,它会抛出一个它找不到它的错误。

app.post('/api/issueBooking', (request, response) => {

Log.findOneAndUpdate({
         bookid: request.body.bookid,
         status: "Available"
       }, {
         $set: {
           status: "Issued"
         }
       }, {
         $push: {
           "details": {
             issueby: "issueByHere",
             issuedate: "issueDateHere",
             returndate: "returnDateHere"
           }
         },
         {
           upsert: true
         }).then((log) => {

         if (!log) {
           return Promise.reject({
             status_code: 404,
             message: "Log not found."
           })
         }

         response.status(200).send("OK");

       }).catch((error) => {
         response.status(error.status_code).send(error.message);
      })
  });

0
投票

该错误可能是因为您没有正确更新详细信息字段。正如我在您的架构中看到的那样,您已将details定义为[],但您使用对象{}更新它。你必须解决这个问题。但我认为你可以让脚本变得更好。该声明:

Logs.findOneAndUpdate({bookid: req.body.bookid}, {$set: {status:"Issued"}}, {$push: {details:detail}}, {upsert: true}, function(err,doc) {

似乎多余。您已经拥有需要更新的文档:

Logs.findOne({bookid: req.body.bookid}).then((doc) => {

得到这个doc后,只需修改你想要的任何类似于javascript对象并做doc.save

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