我正在尝试编写一个扫描未知数字的函数最多10行到一个数组中,最后返回数字的行数。这是代码本身-
for (int i = 0; i < n; i++) {
for (int j = 0; j < DEST; j++)
{
if (scanf("%lf", &flightsPrices[i][j]) != EOF) {
if (flightsPrices[i][j] <= 0) {
errorPrice(i);
exit(-i);
}
}
else return i;
}
}
return 1;
问题是我似乎只获得返回值1和0。我不知道为什么,不胜感激一些指导。谢谢大家!
我将更改条件和返回的值,类似这样
int ask_prices(size_t n, size_t DEST, double flightsPrices[n][DEST])
{
for (size_t i = 0; i < n; i++)
{
for (size_t j = 0; j < DEST; j++)
{
if ( scanf("%lf", &flightsPrices[i][j]) == 1)
{ // ^^^^ If a double is read
if (flightsPrices[i][j] <= 0)
{
errorPrice(i);
return i; // <-- This price is wrong, but not the others.
}
}
else
return i;
}
}
return n; // All the prices were correctly read
}