我如何放弃独特?它干扰了groupby和qcut。
df0 = psql.read_frame(sql_query,conn)
df = df0.sort(['industry','C'], ascending=[False,True] )
这是我的数据帧:
id industry C
5 28 other industry 0.22
9 32 Specialty Eateries 0.60
10 33 Restaurants 0.84
1 22 Processed & Packaged Goods 0.07
0 21 Processed & Packaged Goods 0.14
8 31 Processed & Packaged Goods 0.43
11 34 Major Integrated Oil & Gas 0.07
14 37 Major Integrated Oil & Gas 0.50
15 38 Independent Oil & Gas 0.06
18 41 Independent Oil & Gas 0.06
19 42 Independent Oil & Gas 0.13
12 35 Independent Oil & Gas 0.43
16 39 Independent Oil & Gas 0.65
17 40 Independent Oil & Gas 0.91
13 36 Independent Oil & Gas 2.25
2 25 Food - Major Diversified 0.35
3 26 Beverages - Soft Drinks 0.54
4 27 Beverages - Soft Drinks 0.73
6 29 Beverages - Brewers 0.19
7 30 Beverages - Brewers 0.21
而且我使用了pandas and qcut的以下代码对“C”列进行排名,这对我来说很糟糕。
df['rank'] = df.groupby(['industry'])['C'].transform(lambda x: pd.qcut(x,5, labels=range(1,6)))
经过一番研究,qcut抛出错误的原因是因为行业专栏reference to error和another ref to err的独特价值。
虽然,我仍然希望能够排名而不抛出唯一(唯一应该赋值1),如果可能的话。但是经过这么多尝试之后,我确信qcut无法处理独特的问题,所以我愿意为了让qcut乐于做其事而放弃独特。
但如果还有另一种方式,我很想知道。我非常感谢你的帮助。
以防任何人仍然想要这样做。你应该能够通过只选择重复项来做到这一点?
df = df[df['industry'].duplicated(keep=False)]