这是我有的json数据。我需要 'homescorepoints' + 'homeframepointsadj' 和/或 'awayscorepoints' + 'awayframepointsadj'...
"512830": {
"compname": "VNEA Vegas League",
"grade": "",
"hometeamlabel": "Pool Tang Clan",
"homeshortlabel": "Pool Tang Clan",
"awayteamlabel": "All Shades",
"awayshortlabel": "All Shades",
"homescore": 11,
"homescorepoints": "187",
"homeframepointsadj": "5",
"awayscore": 14,
"awayscorepoints": "178",
"awayframepointsadj": "0",
}
了解基本数组。减少添加多次出现的说“awayscore”,但我有一个心理障碍将两个单独的对象值添加在一起。
假设您想对这个示例对象的值求和:.reduce() 接受数组,那么您可以对对象使用 Object.values() 方法来获取数组,而不是像这样使用 .reduce():
const jsonData = {
"512830": {
"compname": "VNEA Vegas League",
"grade": "",
"hometeamlabel": "Pool Tang Clan",
"homeshortlabel": "Pool Tang Clan",
"awayteamlabel": "All Shades",
"awayshortlabel": "All Shades",
"homescore": 11,
"homescorepoints": "187",
"homeframepointsadj": "5",
"awayscore": 14,
"awayscorepoints": "178",
"awayframepointsadj": "0",
}
};
const calculateScore = (data, type) =>
Object.values(data).reduce((acc, curr) =>
acc + parseInt(curr[`${type}scorepoints`]) + parseInt(curr[`${type}framepointsadj`]), 0);
const homeScore = calculateScore(jsonData, 'home');
const awayScore = calculateScore(jsonData, 'away');
console.log(homeScore);
console.log(awayScore);