无法读取通过hyper :: client :: Client发出HTTP请求的简单有效负载：不满足特征绑定`Body：Future`

Question

我试图将Result转换为Buffer：

let ufc_root: String =
    String::from("https://www.ufc.com/athletes/all?filters%5B0%5D=status%3A23");
// let ufc_root: String = String::from("https://www.google.com");
let https = HttpsConnector::new(4).unwrap();
let client = Client::builder().build::<_, hyper::Body>(https);

client
    .get(ufc_root.parse::<hyper::Uri>().unwrap())
    .and_then(|res| {
        println!("http status code: {}", res.status());
        println!("http response headers:\n{:?}: ", res.headers());
        res.into_body()
    })
    .from_err::<WebScrapeError>()
    .and_then(|body| {
        body.for_each(|chunk| {
            println!("{}", chunk.into_bytes());
        });

        let jon_jones = Subject {
            name: "Jon Jones".to_string(),
            link: "http://www.jonjones.com".to_string(),
        };
        let subjects = vec![jon_jones];
        Ok(subjects)
    })
    .from_err()

error[E0277]: the trait bound `hyper::Body: hyper::rt::Future` is not satisfied
  --> src/scrapper.rs:24:14
   |
24 |             .and_then(|res| {
   |              ^^^^^^^^ the trait `hyper::rt::Future` is not implemented for `hyper::Body`
   |
   = note: required because of the requirements on the impl of `futures::future::IntoFuture` for `hyper::Body`

error[E0599]: no method named `from_err` found for type `futures::future::and_then::AndThen<hyper::client::ResponseFuture, hyper::Body, [closure@src/scrapper.rs:24:23: 28:14]>` in the current scope
  --> src/scrapper.rs:29:14
   |
29 |             .from_err::<WebScrapeError>()
   |              ^^^^^^^^
   |
   = note: the method `from_err` exists but the following trait bounds were not satisfied:
           `&mut futures::future::and_then::AndThen<hyper::client::ResponseFuture, hyper::Body, [closure@src/scrapper.rs:24:23: 28:14]> : hyper::rt::Future`
           `&mut futures::future::and_then::AndThen<hyper::client::ResponseFuture, hyper::Body, [closure@src/scrapper.rs:24:23: 28:14]> : hyper::rt::Stream`
           `futures::future::and_then::AndThen<hyper::client::ResponseFuture, hyper::Body, [closure@src/scrapper.rs:24:23: 28:14]> : hyper::rt::Future`

为什么不编译？

Answer 1

and_then必须回归未来，或通过IntoFuture特征可以转化为未来的东西。你将返回res.into_body()，这不是一个未来 - it's actually a stream。

要使其工作，您需要将该流转换为表示已完全读取的正文的未来。这里有几种选择：

• res.into_body().concat2()，它将所有读取的字节连接成一个缓冲区
• res.into_body().collect()，它将所有字节块收集到Vec中
• res.into_body().into_future()，它将解析为包含流中第一个项目的元组，以及流本身的其余部分（即(T, Stream<Item = T>)）

in the Hyper docs就是一个例子。