为什么第n个子选择器不起作用?

问题描述 投票:0回答:5

我正在使用

nth-child
选择器为不同的社交图标添加背景图像。然而,所有图标看起来都是一样的。我做错了什么?

.social-logo {
    display: inline-block;
    width: 24px;
    height: 24px;
    transition: background-image .2s;
}

#social-links div:nth-child(1) {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-linkedin.svg');
}

#social-links div:nth-child(1):hover {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-linkedin-copy.svg');
}

#social-links div:nth-child(2) {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-dribbble.svg');
}

#social-links div:nth-child(2):hover {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-dribbble-copy.svg');
}

#social-links div:nth-child(3) {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-email.svg');
}

#social-links div:nth-child(3):hover {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-email-copy.svg');
}

#social-links div:nth-child(4) {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-insta.svg');
}

#social-links div:nth-child(4):hover {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-insta-copy.svg');
}
<div id="social-links">
  <a href=""><div class="social-logo"></div></a>
  <a href=""><div class="social-logo"></div></a>
  <a href=""><div class="social-logo"></div></a>
  <a href=""><div class="social-logo"></div></a>
</div>

html css css-selectors
5个回答
64
投票

nth-child
选择器计算兄弟元素(即具有相同父元素的元素)。

在 HTML 结构中,

div.social-logo
始终是
a
的第一个、最后一个和唯一的子级。所以
nth-child
只有一个元素需要计数。

但是,有多个锚元素,所有这些元素都是同级元素(

#social-links
的子元素),因此
nth-child
可以定位每一个。

#social-links a:nth-child(1) div 
#social-links a:nth-child(2) div 
#social-links a:nth-child(3) div 
              .
              .
              .

18
投票

在“:”之前添加空格 示例:-

tr :nth-child(2)
{
    text-align: right;
}

4
投票

我想提一下,在我的例子中,当使用 React 和 node-sass 时,如果我只传递

nth-child
,则
1
属性不起作用,我需要指定
1n
才能使其工作。所以最终它的工作原理是:

.myClass {
  &:nth-child(1n)     { color: red; }
  &:nth-child(2n + 1) { color: blue; }
}

2
投票

试试这个!

<div id="social-links">
  <a href=""><div class="social-logo"></div></a>
  <a href=""><div class="social-logo"></div></a>
  <a href=""><div class="social-logo"></div></a>
  <a href=""><div class="social-logo"></div></a>
</div>

CSS

.social-logo {
    display: inline-block;
    width: 24px;
    height: 24px;
    transition: background-image .2s;
}

#social-links a:nth-child(1) .social-logo {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-linkedin.svg');
}

#social-links a:nth-child(1):hover .social-logo {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-linkedin-copy.svg');
}

#social-links a:nth-child(2) .social-logo {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-dribbble.svg');
}

#social-links a:nth-child(2):hover .social-logo {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-dribbble-copy.svg');
}

#social-links a:nth-child(3) .social-logo {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-email.svg');
}

#social-links a:nth-child(3):hover .social-logo {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-email-copy.svg');
}

#social-links a:nth-child(4) .social-logo {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-insta.svg');
}

#social-links a:nth-child(4):hover .social-logo {
    background-image: url('https://mysql-raigovind93.c9users.io/Cally%20Dai//img/footer/logo-insta-copy.svg');
}

现场演示 - https://jsfiddle.net/g59wa8uf/


1
投票

在我的测试页面上,这是因为

<hr />
标签会破坏选择器逻辑的计数。

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