所欠所得税计算不正确

Question

此程序将通过输入您的收入和婚姻状况来计算您的税级，s 表示单身，m 表示已婚。
该程序将提示您输入收入，然后输入婚姻状况。但它不计算所欠所得税，始终显示 $0.00。任何帮助，将不胜感激。非常感谢！

这是迄今为止我的代码：

   int taxBracket (double income, char maritalStatus);
   double calculateTax(double income, int taxBracket);
   int main() {
   double income;
   char maritalStatus;

   int taxBracketValue;
   printf("Enter income: ");
   scanf("%le", &income);
   printf("Enter marital status (s for single, m for married): ");
   scanf(" %c", &maritalStatus);
   taxBracketValue = taxBracket(income, maritalStatus);
   if(taxBracketValue == -1) {
   printf("Invalid marital status.\n");
   return 1;
   }
   double tax = calculateTax(income, taxBracketValue);
   printf("Income tax is $%.2f\n", tax);
   return 0;
   }
   int taxBracket(double income, char maritalStatus) {
   if (maritalStatus == 's') {
   if(income < 15000)
   return 0;
   else if (income >= 15000 && income < 50000)
   return 1;
   else if (income >= 50000 && income < 90000)
   return 2;
   else if (income >=90000 && income < 160000)
   return 3;
   else
   return 4;
   }
   else if (maritalStatus == 'm') {
   if (income < 30000)
   return 0;
   else if (income>= 30000 && income < 80000)
   return 1;
   else if (income>= 80000 && income < 140000)
   return 2;
   else if (income >= 140000 && income < 220000)
   return 3;
   else
   return 4;
   }
   return -1; 
   }
   double calculateTax(double income, int taXBracket) {
   double tax = 0.0;
   int taxBracket;
   switch(taxBracket) {
   case 0:
   tax = 0.0;
   break;
   case 1:
   tax = income * 0.10;
   break;
   case 2:
   tax = income * 0.15;
   break;
   case 3:
   tax = income * 0.23;
   break;
   case 4:
   tax = income * 0.33;
   break;
   default:;
   break;
   }
   return tax;
   }
   

Answer 1

1. 如果格式不当，代码将难以阅读。
2. 在

   calculateTax()

   中，局部变量

   taxBracket

   未初始化，但您想使用大写不同的参数。这是您的主要问题，您的编译器应该为未初始化的变量生成警告。
3. 缺少 I/O 功能的包含

#include <stdio.h>

int taxbracket(double income, char maritalstatus) {
    if (maritalstatus == 's') {
        if(income < 15000)
            return 0;
        else if (income >= 15000 && income < 50000)
            return 1;
        else if (income >= 50000 && income < 90000)
            return 2;
        else if (income >=90000 && income < 160000)
            return 3;
        else
            return 4;
    }
    else if (maritalstatus == 'm') {
        if (income < 30000)
            return 0;
        else if (income>= 30000 && income < 80000)
            return 1;
        else if (income>= 80000 && income < 140000)
            return 2;
        else if (income >= 140000 && income < 220000)
            return 3;
        else
            return 4;
    }
    return -1;
}

double calculatetax(double income, int taxbracket) {
    double tax = 0.0;
    switch(taxbracket) {
        case 0:
            tax = 0.0;
            break;
        case 1:
            tax = income * 0.10;
            break;
        case 2:
            tax = income * 0.15;
            break;
        case 3:
            tax = income * 0.23;
            break;
        case 4:
            tax = income * 0.33;
            break;
        default:;
            break;
    }
    return tax;
}

int main() {
    double income;
    char maritalstatus;

    int taxbracketvalue;
    printf("enter income: ");
    scanf("%le", &income);
    printf("enter marital status (s for single, m for married): ");
    scanf(" %c", &maritalstatus);
    taxbracketvalue = taxbracket(income, maritalstatus);
    if(taxbracketvalue == -1) {
        printf("invalid marital status.\n");
        return 1;
    }
    double tax = calculatetax(income, taxbracketvalue);
    printf("income tax is $%.2f\n", tax);
    return 0;
}

和示例运行：

Enter income: 30000
Enter marital status (s for single, m for married): s
Income tax is $3000.00