如何用java播放.wav文件

Question

我正在尝试用 Java 播放 *.wav 文件。我希望它执行以下操作：
按下按钮时，会发出短促的蜂鸣声。

我用谷歌搜索了它，但大部分代码都不起作用。有人能给我一个简单的代码片段来播放 .wav 文件吗？

Answer 1

最后我成功地做到了以下几点并且效果很好

import java.io.File;
import java.io.IOException;

import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.LineUnavailableException;
import javax.sound.sampled.SourceDataLine;

public class MakeSound {

    private final int BUFFER_SIZE = 128000;
    private File soundFile;
    private AudioInputStream audioStream;
    private AudioFormat audioFormat;
    private SourceDataLine sourceLine;

    /**
     * @param filename the name of the file that is going to be played
     */
    public void playSound(String filename){

        String strFilename = filename;

        try {
            soundFile = new File(strFilename);
        } catch (Exception e) {
            e.printStackTrace();
            System.exit(1);
        }

        try {
            audioStream = AudioSystem.getAudioInputStream(soundFile);
        } catch (Exception e){
            e.printStackTrace();
            System.exit(1);
        }

        audioFormat = audioStream.getFormat();

        DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat);
        try {
            sourceLine = (SourceDataLine) AudioSystem.getLine(info);
            sourceLine.open(audioFormat);
        } catch (LineUnavailableException e) {
            e.printStackTrace();
            System.exit(1);
        } catch (Exception e) {
            e.printStackTrace();
            System.exit(1);
        }

        sourceLine.start();

        int nBytesRead = 0;
        byte[] abData = new byte[BUFFER_SIZE];
        while (nBytesRead != -1) {
            try {
                nBytesRead = audioStream.read(abData, 0, abData.length);
            } catch (IOException e) {
                e.printStackTrace();
            }
            if (nBytesRead >= 0) {
                @SuppressWarnings("unused")
                int nBytesWritten = sourceLine.write(abData, 0, nBytesRead);
            }
        }

        sourceLine.drain();
        sourceLine.close();
    }
}

Answer 2

这是我在不使用阳光的情况下可以想到的最优雅的形式。*：

import java.io.*;
import javax.sound.sampled.*;

try {
    File yourFile;
    AudioInputStream stream;
    AudioFormat format;
    DataLine.Info info;
    Clip clip;

    stream = AudioSystem.getAudioInputStream(yourFile);
    format = stream.getFormat();
    info = new DataLine.Info(Clip.class, format);
    clip = (Clip) AudioSystem.getLine(info);
    clip.open(stream);
    clip.start();
}
catch (Exception e) {
    //whatevers
}

Answer 3

最短形式（无需安装随机库）？

public static void play(String filename)
{
    try
    {
        Clip clip = AudioSystem.getClip();
        clip.open(AudioSystem.getAudioInputStream(new File(filename)));
        clip.start();
    }
    catch (Exception exc)
    {
        exc.printStackTrace(System.out);
    }
}

唯一的问题是没有好的方法可以让这个方法在 *.wav 完成后阻塞关闭并处理数据。

clip.drain()

表示它被阻塞，但事实并非如此。该剪辑未在之后

start()

运行。我发现唯一可行但丑陋的方法是：

// ...
clip.start();
while (!clip.isRunning())
    Thread.sleep(10);
while (clip.isRunning())
    Thread.sleep(10);
clip.close();

Answer 4

您可以使用事件侦听器在播放后关闭剪辑

import java.io.File;
import javax.sound.sampled.*;

public void play(File file) 
{
    try
    {
        final Clip clip = (Clip)AudioSystem.getLine(new Line.Info(Clip.class));

        clip.addLineListener(new LineListener()
        {
            @Override
            public void update(LineEvent event)
            {
                if (event.getType() == LineEvent.Type.STOP)
                    clip.close();
            }
        });

        clip.open(AudioSystem.getAudioInputStream(file));
        clip.start();
    }
    catch (Exception exc)
    {
        exc.printStackTrace(System.out);
    }
}

Answer 5

这里的代码片段工作正常，用 Windows 声音进行了测试：

public static void main(String[] args) {
        AePlayWave aw = new AePlayWave( "C:\\WINDOWS\\Media\\tada.wav" );
        aw.start();     
}

Answer 6

将播放 WAV 文件的类，阻塞直到声音播放完毕：

class Sound implements Playable {

    private final Path wavPath;
    private final CyclicBarrier barrier = new CyclicBarrier(2);

    Sound(final Path wavPath) {

        this.wavPath = wavPath;
    }

    @Override
    public void play() throws LineUnavailableException, IOException, UnsupportedAudioFileException {

        try (final AudioInputStream audioIn = AudioSystem.getAudioInputStream(wavPath.toFile());
             final Clip clip = AudioSystem.getClip()) {

            listenForEndOf(clip);
            clip.open(audioIn);
            clip.start();
            waitForSoundEnd();
        }
    }

    private void listenForEndOf(final Clip clip) {

        clip.addLineListener(event -> {
            if (event.getType() == LineEvent.Type.STOP) waitOnBarrier();
        });
    }

    private void waitOnBarrier() {

        try {

            barrier.await();
        } catch (final InterruptedException ignored) {
        } catch (final BrokenBarrierException e) {

            throw new RuntimeException(e);
        }
    }

    private void waitForSoundEnd() {

        waitOnBarrier();
    }
}

Answer 7

另一种使用

AudioInputStream

 的方法：

import java.io.File;

import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.Clip;
import javax.sound.sampled.Line;
import javax.sound.sampled.LineEvent;
import javax.sound.sampled.LineListener;
import javax.swing.JDialog;
import javax.swing.JFileChooser;

public class CoreJavaSound extends Object implements LineListener {
    File soundFile;

    JDialog playingDialog;

    Clip clip;

    public static void main(String[] args) throws Exception {
        CoreJavaSound s = new CoreJavaSound();
    }

    public CoreJavaSound() throws Exception {
        JFileChooser chooser = new JFileChooser();
        chooser.showOpenDialog(null);
        soundFile = chooser.getSelectedFile();

        System.out.println("Playing " + soundFile.getName());

        Line.Info linfo = new Line.Info(Clip.class);
        Line line = AudioSystem.getLine(linfo);
        clip = (Clip) line;
        clip.addLineListener(this);
        AudioInputStream ais = AudioSystem.getAudioInputStream(soundFile);
        clip.open(ais);
        clip.start();
    }

    public void update(LineEvent le) {
        LineEvent.Type type = le.getType();
        if (type == LineEvent.Type.OPEN) {
            System.out.println("OPEN");
        } else if (type == LineEvent.Type.CLOSE) {
            System.out.println("CLOSE");
            System.exit(0);
        } else if (type == LineEvent.Type.START) {
            System.out.println("START");
            playingDialog.setVisible(true);
        } else if (type == LineEvent.Type.STOP) {
            System.out.println("STOP");
            playingDialog.setVisible(false);
            clip.close();
        }
    }
}

Answer 8

没有java反射的解决方案

DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat)

Java 反射会降低性能。运行：

java playsound absoluteFilePathTo/file.wav

import javax.sound.sampled.*;
import java.io.*;
public class playsound {

    public static void main (String args[]) throws Exception {
        playSound (args[0]);
    }

    public static void playSound () throws Exception {
        AudioInputStream 
        audioStream = AudioSystem.getAudioInputStream(new File (filename));

        int BUFFER_SIZE = 128000;
        AudioFormat audioFormat = null;
        SourceDataLine sourceLine = null;

        audioFormat = audioStream.getFormat();

        sourceLine = AudioSystem.getSourceDataLine(audioFormat);
        sourceLine.open(audioFormat);
        sourceLine.start();

        int nBytesRead = 0;
        byte[] abData = new byte[BUFFER_SIZE];
        while (nBytesRead != -1) {
            try {
                nBytesRead = 
                audioStream.read(abData, 0, abData.length);
            } catch (IOException e) {
                e.printStackTrace();
            }

            if (nBytesRead >= 0) {
                int nBytesWritten = sourceLine.write(abData, 0, nBytesRead);
            }
        }

        sourceLine.drain();
        sourceLine.close();
    }

}

Answer 9

您也可以这样使用 AudioStream：

import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;

import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;

import sun.audio.AudioPlayer;
import sun.audio.AudioStream;

public class AudioWizz extends JPanel implements ActionListener {

    private static final long serialVersionUID = 1L; //you like your cereal and the program likes their "serial"

    static AudioWizz a;
    static JButton playBuddon;
    static JFrame frame;

    public static void main(String arguments[]){

        frame= new JFrame("AudioWizz");
        frame.setSize(300,300);
        frame.setVisible(true);
        a= new AudioWizz();
        playBuddon= new JButton("PUSH ME");
        playBuddon.setBounds(10,10,80,30);
        playBuddon.addActionListener(a);

        frame.add(playBuddon);
        frame.add(a);
    }

    public void actionPerformed(ActionEvent e){ //an eventListener
        if (e.getSource() == playBuddon) {
            try {
                InputStream in = new FileInputStream("*.wav");
                AudioStream sound = new AudioStream(in);
                AudioPlayer.player.start(sound);
            } catch(FileNotFoundException e1) {
                e1.printStackTrace();
            } catch (IOException e1) {
                e1.printStackTrace();
            }
        }
    }

}

Answer 10

我采用了@greenLizard 的代码并使其更加健壮。

AudioInputStream
```
。
```

BufferedInputStream

。

AudioSystem

getAudioInputStream

 偶尔会抛出

IOException

，因为

getAutoInputSytream

 方法无法备份输入流并重新开始。

希望没有更多的例外情况。

这是修改后的代码。

ErrorDisplayDialog 在 Java Swing 应用程序中将异常显示为 JDialog

。  只需替换为

e.printStackTrace();

即可。

private void playWavFile(String fileName) {
    InputStream inputStream = getClass().getResourceAsStream(fileName);
    BufferedInputStream bufferedInputStream = new BufferedInputStream(
            inputStream);
    AudioInputStream audioStream = null;
    AudioFormat audioFormat = null;

    try {
        audioStream = AudioSystem.getAudioInputStream(bufferedInputStream);
        audioFormat = audioStream.getFormat();
    } catch (UnsupportedAudioFileException e) {
        new ErrorDisplayDialog(view.getFrame(),
                "UnsupportedAudioFileException", e);
        return;
    } catch (IOException e) {
        new ErrorDisplayDialog(view.getFrame(), "IOException", e);
        return;
    }

    DataLine.Info info = new DataLine.Info(SourceDataLine.class,
            audioFormat);
    SourceDataLine sourceLine;
    try {
        sourceLine = (SourceDataLine) AudioSystem.getLine(info);
        sourceLine.open(audioFormat);
    } catch (LineUnavailableException e) {
        new ErrorDisplayDialog(view.getFrame(), "LineUnavailableException",
                e);
        return;
    }

    sourceLine.start();

    int nBytesRead = 0;
    byte[] abData = new byte[128000];
    while (nBytesRead != -1) {
        try {
            nBytesRead = audioStream.read(abData, 0, abData.length);
        } catch (IOException e) {
            new ErrorDisplayDialog(view.getFrame(), "IOException", e);
            return;
        }

        if (nBytesRead >= 0) {
            sourceLine.write(abData, 0, nBytesRead);
        }
    }

    sourceLine.drain();
    sourceLine.close();

    try {
        audioStream.close();
    } catch (IOException e) {
        new ErrorDisplayDialog(view.getFrame(), "IOException", e);
    }
}

Answer 11

我对迷你我写的简短形式做了一些改进。为了避免将来出现问题，所有打开的输入流都应该关闭。

    private void play(String filename) {
    try(AudioInputStream ais = AudioSystem.getAudioInputStream(new File(filename))) {
        Clip clip = AudioSystem.getClip();
        clip.open(ais);
        clip.start();
    } catch (Exception exc) {
        exc.printStackTrace(System.out);
    }
}

如何用java播放.wav文件

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如何用java播放.wav文件

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