如果不是True，如何跳过WebDriverWait函数？

Question

英文有点差。我只是在做一个简单的Instagram机器人，该机器人首先从txt文件中获取用户名和密码，然后将其登录到网站中，但是“ Turn on Notification”仅在首次登录时弹出。每当机器人使用第二个帐户登录时，它都不会弹出。我希望WebdriverWait如果找不到任何元素，则忽略它。如果其他帐户中没有弹出“打开通知”，我希望它忽略。

我要删除的代码将打开“打开通知”。

pop_up = ui.WebDriverWait(browser, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, ".aOOlW.HoLwm"))).click() # Remove notification
sleep(4)

我的整个代码

from time import sleep
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from getpass import getpass

from selenium.webdriver.support import ui
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By


# Create a list of username, password pairs from your file.
username_password_list = list()
with open("C:\\Users\\user\\AppData\\Roaming\\JetBrains\\PyCharmCE2020.1\\scratches\\detail.txt") as file:
 for line in file:
   user, password = line.split(':')
   username_password_list.append((user, password))

browser = webdriver.Firefox() # Runs firefox
browser.implicitly_wait(5)

browser.get('https://www.instagram.com/') # Web address to load

for user, password in username_password_list:
class Main:
    username_input = browser.find_element_by_css_selector('input[name="username"]') # Finds username field
    password_input = browser.find_element_by_css_selector('input[name="password"]') # Finds password field

    username_input.send_keys(user) # Input username
    password_input.send_keys(password) # Input password

    login_button = browser.find_element_by_xpath('//button[@type="submit"]') # Finds login button
    login_button.click() # Click login button

    pop_up = ui.WebDriverWait(browser, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, ".aOOlW.HoLwm"))).click() # Remove notification
    sleep(4)

class SearchBar:
    Search = browser.find_element_by_xpath('//input[contains(@class, "XTCLo x3qfX")]') # Find search bar
    Search.send_keys("Any_Username") # Input
    browser.find_element_by_class_name("yCE8d  ").click() # Search
    sleep(5)

    browser.find_element_by_xpath('//span[@class="vBF20 _1OSdk"]').click() # Finds follow button and Click
    sleep(5)

class Logout:
    browser.find_element_by_xpath('//*[@id="react-root"]/section/nav/div[2]/div/div/div[3]/div/div[5]').click() # Go to profile
    sleep(5)

    browser.find_element_by_xpath('//*[@id="react-root"]/section/main/div/header/section/div[1]/div/button').click() # Click settings
    sleep(5)

    browser.find_element_by_xpath('/html/body/div[4]/div/div/div/button[9]').click() # Click logout
    sleep(5)

browser.close()

Answer 1

您可以使用try/except块来完成：

try:
    ui.WebDriverWait(browser, 5).until(EC.element_to_be_clickable(
        (By.CSS_SELECTOR, ".aOOlW.HoLwm"))).click()
except:
    pass

希望对您有帮助！