从sqlite恢复数据不起作用

问题描述 投票:0回答:1

我想在sqlite中插入后检索我的文章,但是我应该检索它们的变量是null。

这是这篇文章的延续:Function that does not execute

我有一个sqliteservice.ts,它允许您创建数据库和表,然后插入和检索数据。插入数据但我无法在变量中检索它。我在我的页面的构造函数中调用我的函数。

我的服务插入数据并调用函数来检索它们:

      public saveAllArticles(article) {

    let insertions: Array<Promise<any>> = [];
    for (let data in article) {
      insertions.push(this.db.executeSql("INSERT INTO `all_articles` (id, titre) VALUES (" +
        article[data].article_id + ',"' +
        article[data].article_titre + "\")", {}))
      Promise.all(insertions).then(() => {
        console.log("All records have been inserted");
        this.allArticles = this.retrieveAllArticles();
      }).catch(e => {
        console.log("Erreur :" + JSON.stringify(e))
      });
    }
  }

当我做一个console.log(插入);在循环之前,我的控制台没有结果,在循环中有这样的错误:

未捕获(承诺)TypeError:无法读取未定义的属性'push'

而this.allArticles为null。

检索我的文章的函数,这个函数没有调用因为console.log('Retrieve');未显示:

    public retrieveAllArticles() {

    console.log("Retrieve");
    this.allArticles = [];
    this.db.executeSql('SELECT id FROM `all_articles`', {})
      .then((data) => {

      if(data == null) {
        console.log('null');
        return;
      }

      if(data.rows) {
        if(data.rows.length > 0) {
          for(let i = 0; i < data.rows.length; i++) {
            this.allArticles.push(data.rows.item(i).article_id);
          }
        }
      }

        return this.allArticles;
    });
  }

我的页面的构造函数:

  allArticles: any;
  observable$;

  constructor(public navCtrl: NavController,
              public modalCtrl: ModalController,
              protected articlesService: ArticlesService,
              protected sqliteService: SqliteService,
              private network: Network,
              public toastCtrl: ToastController,
              public platform: Platform)
  {
    this.observable$ = this.articlesService.getAllArticles();

    if (this.platform.is('cordova')) {
      sqliteService.createDatabaseFile();

      this.articlesService.getAllArticles().subscribe(article => {
        this.allArticles = article;
        this.sqliteService.saveAllArticles(this.allArticles);
      });

      this.allArticles = this.sqliteService.allArticles;
    }
  }
javascript angular sqlite typescript ionic-framework
1个回答
0
投票

saveAllArticles有问题,它可能看起来像这样:

public saveAllArticles(article) {
  return Promise.all(//return something so you know when saveAllArticles is done
    //assuming article is an array if it's itterable you may try Array.from(article)
    article.map(
      data=>
        this.db.executeSql(
          "INSERT INTO `all_articles` (id, titre) VALUES (" +
            article[data].article_id + ',"' +
            article[data].article_titre + "\")"
          ,{}
        )
    )
  )
  .then(() => {
    console.log("All records have been inserted");
    this.allArticles = this.retrieveAllArticles();
  }).catch(e => {
    console.log("Erreur :" + JSON.stringify(e))
  });
}

retrieveAllArticles返回undefined,不确定这是否是你想要的。您可能希望该函数返回一些内容。

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