我如何使用另一个函数终止一个while循环。 （井字游戏）] <<

Question

我正在用Python编写井字游戏程序。我已经完成了打印棋盘，接受用户输入并实际玩游戏的功能（棋盘每次输入都会变化）。但是，我似乎无法在主output(gboard)函数中运行我的exec()函数来终止while True:循环。这是代码：

def board(gboard):
    print("\n"*10)
    print(gboard[7]+'|'+gboard[8]+'|'+gboard[9])
    print(gboard[4]+'|'+gboard[5]+'|'+gboard[6])
    print(gboard[1]+'|'+gboard[2]+'|'+gboard[3])


def outcome(gboard):
    global ini
    if(gboard[1] == 'X') and (gboard[2] == 'X') and gboard[3] == 'X':
        print('Winner is X!')
        ini = 0
        return ini



def exec():
    move_counter = 0
    ini = 1
    winner = 'X'
    outcomes = ['X','O']

    print("Welcome to Tic Tac Toe!")
    print("Here's how the game works:\nEach number on the keypad represents a place on the table.")
    print("For example the number 1 stands for the box in column 1 row 3, while number 6 stands for column 3 row 2.")
    print("You will tell the computer where you wish to play using this system!")
    print("\n"*2+"Here is a visual representation of the board and the key numbers: ")
    print('7|8|9')
    print('4|5|6')
    print('1|2|3')
    print('If you wish to play X in the middle, you tell the computer to place X in position 5. Here is how a blank board will evolve:')
    print(' | | ')
    print(' |X| ')
    print(' | | ')
    print("So. Let's play!")

    player2 = None
    player1 = input('Player 1, would you like to be X or O(represents the letter)?: ')
    player1 = player1.upper()
    if(player1 == 'X'):
        player2 = 'O'
    else:
        player2 = 'X'
    print(f"Ok. Player 1 is {player1} and so that means that Player 2 is {player2}")


    gboard = ['#',' ',' ',' ',' ',' ',' ',' ',' ',' ',' ']
    while True:
        move = int(input('Player 1, where would you like to play?: '))
        gboard[move] = player1
        move_counter += 1
        board(gboard)
        outcome(gboard)
        if(ini == 0) or move_counter == 9:
            break

        move2 = int(input('Player 2, where would you like to play?: '))
        gboard[move2] = player2
        move_counter += 1
        board(gboard)
        outcome(gboard)

        if(ini == 0) or move_counter == 9:
            break





    print('DONE!')
exec()

在该代码中，如果最下面的行都是X，则我只输入了一个获胜条件-这就是我用来测试程序的条件。当我运行该程序，并在X的最后一行输入内容时，会显示“ Winner is X！”。但不会中断while循环。但是，当move_counter达到9时，它将中断while循环。这是执行：

  Welcome to Tic Tac Toe!
Here's how the game works:
Each number on the keypad represents a place on the table.
For example the number 1 stands for the box in column 1 row 3, while number 6 stands for column 3 row 2.
You will tell the computer where you wish to play using this system!


Here is a visual representation of the board and the key numbers:
7|8|9
4|5|6
1|2|3
If you wish to play X in the middle, you tell the computer to place X in position 5. Here is how a blank board will evolve:
 | |
 |X|
 | |
So. Let's play!
Player 1, would you like to be X or O(represents the letter)?: X
Ok. Player 1 is X and so that means that Player 2 is O
Player 1, where would you like to play?: 1
 | |
 | |
X| |
Player 2, where would you like to play?: 4
 | |
O| |
X| |
Player 1, where would you like to play?: 2
 | |
O| |
X|X|
Player 2, where would you like to play?: 5
 | |
O|O|
X|X|
Player 1, where would you like to play?: 3
 | |
O|O|
X|X|X
Winner is X!
Player 2, where would you like to play?:

我不希望程序询问玩家2，他们在确定获胜者之后想在哪里玩。为什么我的结果函数没有突破while循环？

我正在用Python编写井字游戏程序。我已经完成了打印棋盘，接受用户输入并实际玩游戏的功能（棋盘每次输入都会变化）。但是，我似乎无法运行...

Answer 1

似乎ini函数中的exec变量与ini函数中的outcome变量不同（一个是局部变量，一个是全局变量）。您只需在ini函数中将exec声明为全局变量，即可解决此问题，如下所示：

Answer 2

您在exec（）ini = 1中进行了设置，因此即使获胜将其设置为0，也将再次将其设置为1。您可以从执行程序中删除ini = 1并在所有方法上方进行声明，以便在游戏开始时其值为1，在游戏结束时将其设置为0。

Answer 3

为什么我的结果函数没有突破while循环？

Answer 4

全局变量