我有以下代码，我想使用一个大的，居中对齐的按钮，将访问者的网站随机重定向到一个网址之一：
<html>
<head>
<script type="text/javascript">
<!--
// Create an array of the links to choose from:
var links = new Array();
links[0] = "http://www.google.com/";
links[1] = "http://www.bing.com/";
links[2] = "http://www.yahoo.com/";
links[3] = "http://www.apple.com/";
function openLink() {
// Chooses a random link:
var i = Math.floor(Math.random() * links.length);
// Directs the browser to the chosen target:
parent.location = links[i];
return false;
}
//-->
</script>
</head>
<body onload="openLink();">
</body>
</html>
我应该如何调整上述代码来实现这一目标？谢谢你的帮助。
试试这个
<html>
<head>
</head>
<body>
<script>
let links = []; // don't use new Array() anymore
links[0] = "http://www.google.com/";
links[1] = "http://www.bing.com/";
links[2] = "http://www.yahoo.com/";
links[3] = "http://www.apple.com/";
function openLink() {
var i = ~~(Math.random() * links.length);
window.location.href = links[i]; // if must be 'parent' leave as 'parent'
return false;
}
openLink(); // you can also possibly use window.onload = openLink();
</script>
</body>
</html>试试这个代码
<html>
<head>
<script type="text/javascript">
<!--
// Create an array of the links to choose from:
var links = new Array();
links[0] = "http://www.google.com/";
links[1] = "http://www.bing.com/";
links[2] = "http://www.yahoo.com/";
links[3] = "http://www.apple.com/";
function openLink() {
// Chooses a random link:
var i = Math.floor(Math.random() * links.length);
// Directs the browser to the chosen target:
parent.location = links[i];
return false;
}
//-->
</script>
<style>
.btn {
height:50px;
width:200px;
background:#125288;
color:#fff;
font-size:18px;
}
</style>
</head>
<body>
</body>
<center>
<button onclick="openLink();" class='btn'>Try to Click</button>
</center>
</html>