SQL从第三个单词中选择字符串中的所有单词

Question

我的数据集正在变化，现在我的客户名称字段开头还包含两个附加单词，我需要在将数据移到主客户表之前清理这些数据。

我需要做的是在select语句中只保留第二个空格之后的单词。

谁能建议一种方法来做到这一点

即“ZENDUSER ABCABC S ROCCO AL PORTO”需要退回“S ROCCO AL PORTO”

Answer 1

您可以使用CHARINDEX和SUBSTRING执行此操作：

declare @a varchar(200)

set @a = 'ZENDUSER ABCABC S ROCCO AL PORTO'

select  @a, substring(@a, charindex(' ', @a, charindex(' ', @a, 1) + 1) + 1, 200)

Answer 2

DECLARE @cust NVARCHAR(MAX);
SET @cust = N'ZENDUSER ABCABC S ROCCO AL PORTO';

SELECT SUBSTRING(@cust, CHARINDEX(' ', @cust, CHARINDEX(' ', @cust, 0) + 1) + 1,
                  LEN(@cust) - CHARINDEX(' ', @cust, CHARINDEX(' ', @cust, 0) + 1));
 GO


| (No column name) |
| :--------------- |
| S ROCCO AL PORTO |

dbfiddle here

Answer 3

试试这个：

select substring(MyColumn, CHARINDEX(MyColumn, ' ', CHARINDEX(MyColumn, ' ', 1) + 1) + 1, Len(MyColumn)) from MyTable

我知道，这与MJH答案非常类似，但另外，我在Len(MyColumn)方法中使用substring，所以我们确信我们在第二个空格后包含所有字符。另一个答案只需要200个字符。

Answer 4

如果您希望修剪更加动态，即从第5个字开始等，您可以使用以下代码片段。我会将其封装在内联函数中以获得其他功能

    DECLARE @Sentence NVARCHAR(200) = 'ZENDUSER ABCABC S ROCCO AL PORTO'
    DECLARE @Del NVARCHAR(2)= ' '
    DECLARE @WordStart INT = 5

    ;WITH Nums (n) as 
        (
        SELECT TOP (LEN(@Sentence)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL))
        FROM (VALUES (0),(0),(0),(0),(0),(0),(0),(0)) a(n)
        CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) b(n)
        CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) c(n)
        CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) d(n)
        )
    , Main as 
    (
    SELECT N, x.val , Ind , CASE WHEN n = 1 THEN 1  ELSE SUM(Ind) OVER (ORDER BY n) + 1  END Pos
    FROM Nums
        CROSS APPLY 
            (
            VALUES (SUBSTRING(@Sentence,n,1),
            CASE WHEN SUBSTRING(@Sentence,n,1) = @Del THEN 1 ELSE 0 END) 

            ) x(val, Ind)
    )
    , Combine (StrOut) as 
    (
    SELECT LTRIM(RTRIM(STUFF(
            CAST((SELECT ''+ val
            FROM Main
            WHERE Pos >= @WordStart
            FOR XML PATH (''),TYPE) AS NVARCHAR(MAX)),1,0,'')
            )))
     SELECT StrOut 
     FROM Combine

更新：创建一个功能

    CREATE FUNCTION dbo.SentenceSplitter 
    (
    @Sentence NVARCHAR(2000),
    @WordStart INT,
    @Del NVARCHAR(2) = ' ' 
    )
    RETURNS TABLE AS RETURN

        WITH Nums (n) as 
                (
                SELECT TOP (LEN(@Sentence)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL))
                FROM (VALUES (0),(0),(0),(0),(0),(0),(0),(0)) a(n)
                CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) b(n)
                CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) c(n)
                CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) d(n)
                )
            , Main as 
            (
            SELECT N, x.val , Ind , CASE WHEN n = 1 THEN 1  ELSE SUM(Ind) OVER (ORDER BY n) + 1  END Pos
            FROM Nums
                CROSS APPLY 
                    (
                    VALUES (SUBSTRING(@Sentence,n,1),
                    CASE WHEN SUBSTRING(@Sentence,n,1) = @Del THEN 1 ELSE 0 END) 

                    ) x(val, Ind)
            )
            , Combine (StrOut) as 
            (
            SELECT LTRIM(RTRIM(STUFF(
                    CAST((SELECT ''+ val
                    FROM Main
                    WHERE Pos >= @WordStart
                    FOR XML PATH (''),TYPE) AS NVARCHAR(MAX)),1,0,'')
                    )))
             SELECT StrOut 
             FROM Combine

使用案例：

SELECT StrOut
FROM dbo.SentenceSplitter ('ZENDUSER ABCABC S ROCCO AL PORTO', 5, ' ')

将导致：

StrOut
AL PORTO