CodingBat Python：List - 2，sum13

Question

我无法弄清楚为什么我的代码无效。问题是：

返回数组中数字的总和，返回0表示空数组。除了数字13是非常不吉利的，因此它不计算在13之后立即出现的数字也不计算。

sum13（[1,2,2,1]）→6

sum13（[1,1]）→2

sum13（[1,2,2,1,13]）→6

我的答案：

def sum13(nums):
    count = sum(nums)
    for i in range(len(nums)):
        if nums[i] == 13:
            count = count - 13 
            count = count - nums[i+1]
    return count

Answer 1

def sum13(nums):
count = sum(nums)
for i in range(len(nums)):
    if nums[i] == 13:
        # count = count - 13 
        # count = count - nums[i+1]
        #print(nums[:i])
        count = sum(nums[:i])
return count

Answer 2

删除有问题的元素，然后总结剩下的内容。使用生成器使这非常简单

def remove_13(l):
    it = iter(l)
    for x in it:
        if x == 13:
            try:
                next(it)
            except StopIteration:
                return
        else:
            yield x

def sum13(l):
    return sum(remove_13(l))

Answer 3

def sum13(nums):

    if 13 in nums:
        try:
            nums.append(0)
            for i in range(len(nums)):

                if nums[i] == 13:
                    nums.remove(nums[i])
                    nums.remove(nums[i])
                    return sum13(nums)
        except:
            return sum(nums)   
        return sum(nums)


    return sum(nums)