如何获取微调器的所选项目的字符串值？

Question

在我的微调器中，我的值是“男”，“女”和“男和女”。如果有人在微调器中单击“男性”，我想检索该值。我现有的使用spinner.getSelectedItem（）。toString（）的代码提供以下结果：

com.example.kitchen.SpinnerItem@64dd10e

我什至尝试实现.setOnItemSelectedListener（），但这也不起作用。主要活动代码：

public class ManageEventsActivity extends AppCompatActivity {

    String stringCreateEventGender;
    ArrayList<String> arrayUpcomingEventGender = new ArrayList<>();
    ArrayList<SpinnerItem> mGenderList = new ArrayList<>();
    SpinnerAdapter genderAdapter;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_manage_events);

        spinnerCreateEventGender = findViewById(R.id.spinnerCreateEventGender);

        initGenderList();
        genderAdapter = new SpinnerAdapter(this, mGenderList);
        spinnerCreateEventGender.setAdapter(genderAdapter);
    }

    private void initGenderList() {
        mGenderList.add(new SpinnerItem("Male"));
        mGenderList.add(new SpinnerItem("Female"));
        mGenderList.add(new SpinnerItem("Male and female"));
    }
}

Spin​​ner适配器代码：

public class SpinnerAdapter extends ArrayAdapter<SpinnerItem> {

    public SpinnerAdapter(Context context, ArrayList<SpinnerItem> genderList) {
        super(context, 0, genderList);
    }

    @NonNull
    @Override
    public View getView(int position, @Nullable View convertView, @NonNull ViewGroup parent) {
        return initView(position, convertView, parent);
    }

    @Override
    public View getDropDownView(int position, @Nullable View convertView, @NonNull ViewGroup parent) {
        return initView(position, convertView, parent);
    }

    private View initView(int position, View convertView, ViewGroup parent) {
        if (convertView == null) {
            convertView = LayoutInflater.from(getContext()).inflate(
                    R.layout.spinner_layout, parent, false
            );
        }
        TextView textViewItem = convertView.findViewById(R.id.textViewItem);
        SpinnerItem currentItem = getItem(position);
        if (currentItem != null) {
            textViewItem.setText(currentItem.getItem());
        }
        return convertView;
    }
}

微调项代码：

public class SpinnerItem {

    String mItem;

    public SpinnerItem(String item) {
        mItem = item;
    }

    public String getItem() {
        return mItem;
    }
}

Answer 1

您需要将对象强制转换为其原始类型（还要检查其是否不是null）：

@Nullable Object selectedItem = spinner.getSelectedItem();
if (selectedItem != null) { // selectedItem is null if there is nothing selected
    String item = ((SpinnerItem) selectedItem).getItem();
}

或者您应该重写toString方法以返回对象的值：

public class SpinnerItem {

    String mItem;

    public SpinnerItem(String item) {
        mItem = item;
    }

    public String getItem() {
        return mItem;
    }

    @NonNull
    @Override
    public String toString() {
        return mItem;
    }
}

然后spinner.getSelectedItem().toString()将提供正确的结果：

final String item = spinner.getSelectedItem().toString();