如何从node.js Express发送POST请求？

Question

有人可以告诉我从node.js Express发送post请求的最简单方法，包括如何传递和检索一些数据吗？我期待类似 PHP 中的 cURL 的东西。

Answer 1

var request = require('request');
 function updateClient(postData){
            var clientServerOptions = {
                uri: 'http://'+clientHost+''+clientContext,
                body: JSON.stringify(postData),
                method: 'POST',
                headers: {
                    'Content-Type': 'application/json'
                }
            }
            request(clientServerOptions, function (error, response) {
                console.log(error,response.body);
                return;
            });
        }

为此，您的服务器必须类似于：

var express = require('express');
var bodyParser = require('body-parser');
var app = express();
app.use(bodyParser.urlencoded({ extended: false }));
app.use(bodyParser.json())

var port = 9000;

app.post('/sample/put/data', function(req, res) {
    console.log('receiving data ...');
    console.log('body is ',req.body);
    res.send(req.body);
});

// start the server
app.listen(port);
console.log('Server started! At http://localhost:' + port);

Answer 2

你可以这样尝试：

var request = require('request');
request.post({ headers: {'content-type' : 'application/json'}
               , url: <your URL>, body: <req_body in json> }
               , function(error, response, body){
   console.log(body); 
}); 

Answer 3

如此处所述，用于发布请求：

var http = require('http');

var options = {
  host: 'www.host.com',
  path: '/',
  port: '80',
  method: 'POST'
};

callback = function(response) {
  var str = ''
  response.on('data', function (chunk) {
    str += chunk;
  });

  response.on('end', function () {
    console.log(str);
  });
}

var req = http.request(options, callback);
//This is the data we are posting, it needs to be a string or a buffer
req.write("data");
req.end();

Answer 4

在您的服务器端，代码如下所示：

var request = require('request');

app.post('/add', function(req, res){
  console.log(req.body);
  request.post(
    {
    url:'http://localhost:6001/add',
    json: {
      unit_name:req.body.unit_name,
      unit_price:req.body.unit_price
        },
    headers: {
        'Content-Type': 'application/json'
    }
    },
  function(error, response, body){
    // console.log(error);
    // console.log(response);
    console.log(body);
    res.send(body);
  });
  // res.send("body");
});

在接收端服务器代码如下：

app.post('/add', function(req, res){
console.log('received request')
console.log(req.body);
let adunit = new AdUnit(req.body);
adunit.save()
.then(game => {
res.status(200).json({'adUnit':'AdUnit is added successfully'})
})
.catch(err => {
res.status(400).send('unable to save to database');
})
});

Schema 只是两个属性unit_name 和unit_price。

Answer 5

我使用

superagent

，它与 jQuery 类似。

这是文档

演示如下：

var sa = require('superagent');
sa.post('url')
  .send({key: value})
  .end(function(err, res) {
    //TODO
  });

Answer 6

试试这个。它对我有用。

const express = require("express");
const app = express();
app.use(express.json());
const PORT = 3000;

const jobTypes = [
{ id: 1, type: "Interior" },
{ id: 2, type: "Etterior" },
{ id: 3, type: "Roof" },
{ id: 4, type: "Renovations" },
{ id: 5, type: "Roof" },
];

app.post("/api/jobtypes", (req, res) => {
const jobtype = { id: jobTypes.length + 1, type: req.body.type };
jobTypes.push(jobtype);
res.send(jobtype);
});

app.listen(PORT, console.log(`Listening on port ${PORT}....`));