我正在尝试通过多个函数传递表并返回它,但是它只能在某种程度上起作用。我几乎可以肯定它必须与范围界定有关,但是由于我是LUA的新手,所以我无法解决。我尝试将表放在第1行并将其设置为全局,但无济于事。错误:bag参数:预期表,但为零。
function returnToTunnel(movementTable)
for i = table.maxn(movementTable), 1, -1 do --this is where I get the error.
if (movementTable[i] == 1) then
turtle.down()
elseif (movementTable[i] == 2) then
turtle.up()
elseif (movementTable[i] == 3) then
turtle.back()
turtle.turnRight()
elseif (movementTable[i] == 4) then
turtle.back()
turtle.turnLeft()
elseif (movementTable[i] == 5) then
turtle.back()
end
end
end
function mineOre(locationParam, movementTable)
if (locationParam == 1) then
turtle.digUp()
turtle.suckUp()
turtle.up()
table.insert(movementTable, 1)
elseif (locationParam == 2) then
turtle.digDown()
turtle.suckDown()
turtle.down()
table.insert(movementTable, 2)
elseif (locationParam == 3) then
turtle.turnLeft()
turtle.dig()
turtle.suck()
turtle.forward()
table.insert(movementTable, 3)
elseif (locationParam == 4) then
turtle.turnRight()
turtle.dig()
turtle.suck()
turtle.forward()
table.insert(movementTable, 4)
elseif (locationParam == 5) then
turtle.dig()
turtle.suck()
turtle.forward()
table.insert(movementTable, 5)
end
locationParam = oreCheck()
if (locationParam > 0) then
mineOre(locationParam, movementTable)
else
return movementTable
end
end
function digTunnel(tunnelLengthParam)
local oreFound
local movement = {}
for i = 1, tunnelLengthParam do
turtle.dig()
turtle.forward()
oreFound = oreCheck()
if (oreFound > 0) then
movement = mineOre(oreFound, movement)
returnToTunnel(movement)
end
if ((i % 2) == 1) then
turtle.digUp()
turtle.up()
elseif ((i % 2) == 0) then
turtle.digDown()
turtle.down()
end
oreFound = oreCheck()
if (oreFound > 0) then
movement = mineOre(oreFound, movement)
returnToTunnel(movement)
end
end
end
因此,digTunnel函数调用其他两个函数mineOre和returnToTunnel。
我一直在寻找LUA手册和一些网站,但无法弄清楚。谢谢您的帮助!
当locationParam为> 0时,您的功能mineOre不返回表,而是返回nil。