删除字符串的开头和结尾

Question

我有以下字符串：

日wassup = 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;域= .asdf.com;路径= /;安全;仅Http;

我需要删除字符串“ wassup =”的开头，可以使用substr（7，str.length）和字符串“; domain = .asdf.com; path = / ; secure; httponly;“

要删除我尝试使用indexOf（“;”）的结尾，但这仅删除了我需要的一部分。

我想通过一种简单的方法来使代码保持尽可能的干净（全部在一行/尝试中完成）。

Answer 1

let index = wassup.indexOf(';');
wassup.substring(0, index);