if(isset($_POST['post-submit'])){
$post_category_id = $_POST['post_category_id'];
$post_title = $_POST['post_title'];
$post_author = $_POST['post_author'];
$post_tags = $_POST['post_tags'];
$post_status = $_POST['post_status'];
$post_content = $_POST['post_content'];
// SQL Injection
$post_content = mysqli_real_escape_string($connection, $post_content );
$post_date = date('d-m-y');
$post_comment_count = 4;
$post_image = $_FILES['image']['name'];
$post_image_temp = $_FILES['image']['temp_name'];
move_uploaded_file($post_image_temp, "../img/blog/$post_image" );
$query = "INSERT INTO posts(post_image,post_date,post_comment_count, post_category_id, post_title, post_author, post_tags, post_status, post_content) " ;
$query .= "VALUES('$post_image', now(), '$post_comment_count' ,'$post_category_id','$post_title','$post_author','$post_tags','$post_status','$post_content')";
$insert_all_post_query = mysqli_query($connection, $query);
if(!$insert_all_post_query)
{
die("QUERY FAILED" . mysqli_error($connection));
}
else {echo "<h2>Data Sucessfully Updated</h2>";}
}
注意:未定义的索引:C:\ xampp \ htdocs \ cms_admin \ admin \ postCreate.php在第35行中的temp_name
收到此错误-但帖子的插入效果很好
您在列位置使用now()函数
您应该输入列名,例如created_at
如果要在values
中使用当前时间戳记值,请在此处写入now()