我正在使用 RMarkdown 编写报告,并使用 kable 和 kableExtra 来格式化和打印表格。这是我想要的表格看起来像(用 Word 制作):
我正在努力排序垂直居中(顶部和底部
"Number of Incident Occurences"
之间的空间,以便文本在行的中间对齐,在列的左侧。
注意,我正在创建 PDF 报告而不是 html。
这是一个最小的例子:
df <- data.frame(a = letters[1:5], b = 1:5)
names(df) <- c("A very very very very very very very very very very very very very very very very very very long title",
"A short title")
df %>% kable(format = 'latex', linesep = "", align = 'c', escape = F) %>% kable_styling(full_width = T)
这就是输出的样子:
垂直对齐好像是往上推。我遇到了“m”,但它只是中间对齐列。我想知道我是否需要为
align = "m"
的所有行指定一些特殊的东西是row_spec(),但是当我这样做时,它会抱怨......有什么想法吗?
这可以通过添加
extra_css
参数在 HTML 中实现。 (对于那些正在 HTML 中搜索类似解决方案并且只找到这篇文章的人)
column_spec(1,extra_css = "vertical-align:middle;")
似乎没有办法直接在 kable 和 kableExtra 中执行此操作。然而,当通过 kable 将表格构建为 PDF 时,它使用 LaTeX 来构建结果。因此,我们可以将 LaTeX 函数直接集成到表格中。
此解决方案使用
multirow
包。要垂直居中的单元格可以用\\multirow{1}{*}[0pt]{Cell content}
包裹起来,如下:
---
header-includes:
- \usepackage{multirow}
output: pdf_document
---
```{r}
library(knitr)
library(kableExtra)
df <- data.frame(a = letters[1:5], b = 1:5)
names(df) <- c("A very very very very very very very very very very very very very very very very very very long title",
"\\multirow{1}{*}[0pt]{A short title}")
df %>% kable(format = 'latex', linesep = "", align = 'c', escape = F) %>% kable_styling(full_width = T)
```
为了更容易使用它,您可以创建一个函数来为您重命名:
centerText <- function(text){
paste0("\\multirow{1}{*}[0pt]{", text, "}")
}
所以要重命名您运行的列:
centerText("A short title")
截至 2020 年 8 月,column_spec()
包中的
kableExtra
函数有一个
latex_valign
参数。这仅在您还指定列宽时才有效,因此它与
kable_styling(full_width = T)
不兼容
library(knitr)
library(kableExtra)
df <- data.frame(a = letters[1:5], b = 1:5)
names(df) <- c("A very very very very very very very very very very very very very very very very very very long title",
"A short title")
df %>%
kable(format = 'latex',
linesep = "",
align = 'c') %>%
column_spec(1:2,
width = "3in",
latex_valign = "m")