MySql无法将值从一个表添加到另一个表

Question

我的DB看起来：

SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL,ALLOW_INVALID_DATES';

CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET utf8 ;
USE `mydb` ;

CREATE TABLE IF NOT EXISTS `mydb`.`contacts` (
  `idcontact` INT NOT NULL AUTO_INCREMENT,
  `phone` VARCHAR(45) NULL,
  `email` VARCHAR(45) NULL,
  PRIMARY KEY (`idcontact`))
ENGINE = InnoDB;

CREATE TABLE IF NOT EXISTS `mydb`.`adresses` (
  `idadress` INT NOT NULL AUTO_INCREMENT,
  `city` VARCHAR(45) NULL,
  `street` VARCHAR(45) NULL,
  `street_number` VARCHAR(45) NULL,
  PRIMARY KEY (`idadress`))
ENGINE = InnoDB;

CREATE TABLE IF NOT EXISTS `mydb`.`employees` (
  `idemployee` INT NOT NULL AUTO_INCREMENT,
  `name` VARCHAR(45) NULL,
  `surname` VARCHAR(45) NULL,
  `adresses_idadress` INT NOT NULL,
  `contacts_idcontact` INT NOT NULL,
  PRIMARY KEY (`idemployee`),
  INDEX `fk_employees_adresses_idx` (`adresses_idadress` ASC),
  INDEX `fk_employees_contacts1_idx` (`contacts_idcontact` ASC),
  CONSTRAINT `fk_employees_adresses`
    FOREIGN KEY (`adresses_idadress`)
    REFERENCES `mydb`.`adresses` (`idadress`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `fk_employees_contacts1`
    FOREIGN KEY (`contacts_idcontact`)
    REFERENCES `mydb`.`contacts` (`idcontact`)
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB;

SET SQL_MODE=@OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;

然后我插入表格地址和联系人：

insert into mydb.contacts(phone,email) values ('123123123','[email protected]');
insert into mydb.adresses(city,street,street_number) values ('London','28th Street','13');

接下来我想插入员工： insert into mydb.employees(name,surname) values ('Jack','Reaper');

我收到此错误：

错误代码：1452。无法添加或更新子行：外键约束失败（mydb.employees，CONSTRAINT fk_employees_adresses FOREIGN KEY（adresses_idadress）REFERENCES adresses（idadress）ON DELETE NO ACTION ON UPDATE NO ACTION）

我需要做些什么来修复它？

Answer 1

在employee表上插入时，还必须提供address_isaddress和contact_idcontact。没有它，插入物将不会通过。