举个例子,我有一个html表单
<form action="form.php" method="post">
First name:<br>
<input type="text" id="fname" name="fname">
<br>
Last name:<br>
<input type="text" id="lname" name="lname">
<br><br>
<input type="submit" value="Submit">
</form>
和form.php
<?php
$servername = "localhost";
$username = "database1";
$password = "xxxxxxxx";
$dbname = "database1";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//escape variables for security
$fname = mysqli_real_escape_string($conn, $_POST['fname']);
$lname = mysqli_real_escape_string($conn, $_POST['lname']);
$sql = "INSERT INTO mytable (fname,lname)
VALUES ('$fname','$lname')";
if ($conn->query($sql) === TRUE) {
echo "Successfully Saved";
} else {
echo "Error: Go back and Try Again ! " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
form.php将该数据保存到database1
。
我希望将数据与database2
一起保存到另一个数据库database1
。
可能吗 ??如果是,则应在代码中进行哪些更改?
如果不可能,那么可以自动将数据从database1
复制到database2
吗?每当在database1
中添加新行时,它应自动复制到database2
。
我希望相同的数据位于两个不同的数据库中。我怎样才能实现以上任何一种说法?
从php你只需创建与DB的新连接。
<?php
$servername = "localhost";
$username = "database1";
$password = "xxxxxxxx";
$dbname = "database1";
$servernameS = "localhost";
$usernameS = "database2";
$passwordS = "xxxxxxxx";
$dbnameS = "database2";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
$connS = new mysqli($servernameS, $usernameS, $passwordS, $dbnameS);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if ($connS->connect_error) {
die("Connection failed: " . $connS->connect_error);
}
//escape variables for security
$fname = mysqli_real_escape_string($conn, $_POST['fname']);
$lname = mysqli_real_escape_string($conn, $_POST['lname']);
$sql = "INSERT INTO mytable (fname,lname)
VALUES ('$fname','$lname')";
if ($conn->query($sql) === TRUE) {
echo "Successfully Saved";
} else {
echo "Error: Go back and Try Again ! " . $sql . "<br>" . $conn->error;
}
if ($connS->query($sql) === TRUE) {
echo "Successfully Saved";
} else {
echo "Error: Go back and Try Again ! " . $sql . "<br>" . $connS->error;
}
$conn->close();
$connS->close();
?>
你可以使用像mysqli::selectDB method这样的东西:
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "test");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
/* return name of current default database */
if ($result = $mysqli->query("SELECT DATABASE()")) {
$row = $result->fetch_row();
printf("Default database is %s.\n", $row[0]);
$result->close();
}
/* change db to world db */
$mysqli->select_db("world");
/* return name of current default database */
if ($result = $mysqli->query("SELECT DATABASE()")) {
$row = $result->fetch_row();
printf("Default database is %s.\n", $row[0]);
$result->close();
}
$mysqli->close();
?>
看看manual。
类似的question和你一样。