替换破折号并增加相邻地雷的数量

Question

我正在尝试替换这个二维列表中的破折号来表示相邻的地雷数量

grid = [["-", "-", "-", "#", "#"],
        ["-", "#", "-", "-", "-"],
        ["-", "-", "#", "-", "-"],
        ["-", "#", "#", "-", "-"],
        ["-", "-", "-", "-", "-"]]

并按如下方式打印新网格：

1 1 2 # # 
1 # 3 3 2 
2 4 # 2 0
1 # # 2 0
1 2 2 1 0

这是我当前的Python代码

positions = [[-1, -1], [-1, 0], [-1, 1], [0, -1], [0, 1], [1, -1], [1, 0],[1, 1]]
mine = "#"
new_grid = [[[0, mine][count_two == mine] for count_two in row] for row in grid]
def minesweeper(grid):
    count = 0
    for count, value in enumerate(grid):
        for count_two, value_two in enumerate(value):
            for dr, dc in grid:
               if value_two == mine:
                    if count+dr in range(len(grid)) \
                        and count_two+dc in range(len(value)):
                        new_grid[count][count_two] += \
                        grid[count+dr][count_two+dc] == mine
for row in new_grid:
    for count_two in row:
        print(count_two, end=" ")
    print()

但是，它打印以下内容：

0 0 0 # # 
0 # 0 0 0 
0 0 # 0 0
0 # # 0 0
0 0 0 0 0

当我定义 new_grid 变量时，我可以看到第一个 [] 中的 0 导致相邻我的 0 不增加，但我不知道如何修复

Answer 1

你没有调用minesweeper():

positions = [[-1, -1], [-1, 0], [-1, 1], [0, -1], [0, 1], [1, -1], [1, 0],[1, 1]]
mine = "#"
new_grid = [[0, 0, 0, "#", "#"],
            [0, "#", 0, 0, 0],
            [0, 0, "#", 0, 0],
            [0, "#", "#", 0, 0],
            [0, 0, 0, 0, 0]]
def minesweeper(grid):
    count = 0
    for count, value in enumerate(new_grid):
        for count_two, value_two in enumerate(value):
            for dr, dc in positions:
                if count+dr in range(len(new_grid))and count_two+dc in range(len(value)):
                    if new_grid[count+dr][count_two+dc] == mine and grid[count][count_two] != mine:
                        new_grid[count][count_two] += 1
minesweeper(new_grid)
for row in new_grid:
    for count_two in row:
        print(count_two, end=" ")
    print()