我正在使用PlayFramework 2.6与SCALA和mongodb-driver。
在写入时挣扎着使用Eumeration序列化。
当我尝试插入包含枚举字段的对象时,我得到异常:
Caused by: org.bson.codecs.configuration.CodecConfigurationException: Can't find a codec for class scala.Enumeration$Val.
at org.bson.codecs.configuration.CodecCache.getOrThrow(CodecCache.java:46)
at org.bson.codecs.configuration.ProvidersCodecRegistry.get(ProvidersCodecRegistry.java:63)
at org.bson.codecs.configuration.ProvidersCodecRegistry.get(ProvidersCodecRegistry.java:37)
at org.mongodb.scala.bson.codecs.macrocodecs.MacroCodec.writeValue(MacroCodec.scala:167)
at org.mongodb.scala.bson.codecs.macrocodecs.MacroCodec.writeValue$(MacroCodec.scala:162)
我为对象本身创建了编解码器,也试图为枚举类类型创建编解码器,但看起来它是正确的方式。
val routeTypeCodec: CodecProvider = Macros.createCodecProvider[RouteTypeClass]
val routeCodec: CodecProvider = Macros.createCodecProviderIgnoreNone[Route]
列举:
class RouteTypeClass extends TypeReference[RouteType.type]
object RouteType extends Enumeration {
type RouteType = Value
val Repeat, OneTime = Value
}
保存对象:
case class Route(
...
routeType: RouteType
...
);
如何为枚举字段编写编解码器,除了将此字段定义为String。
放弃使用枚举。相反,使用密封的特征和案例类。不是太优雅的解决方案,但有效。
sealed trait RouteType {
def routeType: String
}
case class Repeat() extends RouteType {
override val routeType: String = "Repeat"
}
case class OneTime() extends RouteType {
override val routeType: String = "OneTime"
}
objet RouteType {
def parseFromString(value: String): Option[RouteType] = {
Vector(Repeat(), OneTime().find(_.routeType == value)
}
}
并为这些编写自定义BSON编解码器
import org.bson.{BsonReader, BsonWriter}
import org.bson.codecs.{Codec, DecoderContext, EncoderContext}
class RouteTypeCodec extends Codec[RouteType] {
override def encode(
writer: BsonWriter,
value: RouteType,
encoderContext: EncoderContext
): Unit = writer.writeString(value.routeType)
override def getEncoderClass: Class[RouteType] = classOf[RouteType]
override def decode(reader: BsonReader,
decoderContext: DecoderContext): RouteType= {
val value = reader.readString()
val result = RouteType.parseFromString(value)
if (result.isDefined) result.get else throw new IllegalArgumentException("No such RouteType")
}
}