Swift从Array返回字符串

问题描述 投票:0回答:3

我试图从这个数组中获取一个随机名称作为字符串而不是数字。

I.E:数组通常返回0到9的随机数,我宁愿让它返回0到9表示的字符串,如Preston或James,而不是数字本身。

下面的代码已被破坏,但我希望它可以让你看到我正在尝试做的事情。

 var firstName : [String] = ["Preston", "Ally", "James", "Justin", "Dave", "Bacon", "Bossy",     "Edward", "Edweird" ]

var standardIdent = "First Name:\(firstName[random(0...9)]) Last Name:\(lastName[random(0...5)]) \n Age:\(rand())"
println(standardIdent)

谢谢您的帮助!

arrays macos swift
3个回答
1
投票

你应该使用像arc4random

let firstRandom = Int(arc4random() % 10)
let secondRandom = Int(arc4random() % 6)
var standardIdent = "First Name:\(firstName[firstRandom]) Last Name:\(lastName[secondRandom]) \n Age:\(rand())"

2
投票

你不应该使用arc4random()%算子。这引入了modulo bias

在Swift 4.2及更高版本中,您应该使用randomElement()

let firstNames = ["Preston", "Ally", "James", "Justin", "Dave", "Bacon", "Bossy", "Edward", "Edweird"]
let randomFirstName = firstNames.randomElement()!

或者,如果数组可能为空,请不要使用强制解包运算符,而是执行:

guard let randomFirstName = firstNames.randomElement() else {
    print("array was empty")
    return
}

在4.2之前的Swift版本中,您应该:

  1. 你通常应该使用arc4random_uniform而不是arc4random来消除模偏差。
  2. 您应该使用数组中项目的计数来确定可能的索引值的范围。

从而:

guard firstNames.count > 0 else { ... }
let index = Int(arc4random_uniform(UInt32(firstNames.count)))
let randomFirstName = firstNames[index]

1
投票

更好的是:使用arc4random_uniform来避免模偏差:

var firstName : [String] = ["Preston", "Ally", "James", "Justin", "Dave", "Bacon", "Bossy", "Edward", "Edweird" ]

var lastName : [String] = ["Miller", "Jones", "Jackson", "Smith"]

let firstRandom = Int(arc4random_uniform(UInt32(firstName.count)))
let secondRandom = Int(arc4random_uniform(UInt32(lastName.count)))
var standardIdent = "First Name:\(firstName[firstRandom]) Last Name:\(lastName[secondRandom]) \n Age:\(rand())"
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