我被要求为某电台制作非官方的在线流媒体安卓应用。我有经验的流媒体在Android的某些MP3或什么流。但我不知道 stream url
以提供 mediaPlayer.setDataSource(url)
.
有什么办法可以得到流的网址从官方流媒体页面,例如:。这个电台流?
没有那么难。
如果你看一下这个页面的源码,你会发现它使用的是shoutcast流媒体。
这是流媒体的网址
它返回一个JSON这样的。
{
"Streams": [
{
"StreamId": 3244651,
"Reliability": 92,
"Bandwidth": 64,
"HasPlaylist": false,
"MediaType": "MP3",
"Url": "http://mp3hdfm32.hala.jo:8132",
"Type": "Live"
}
]
}
我相信这就是你所需要的url:http:/mp3hdfm32.hala.jo:8132
编辑了ZygD的python 3.x的答案。
import re
import urllib.request
import string
url1 = input("Please enter a URL from Tunein Radio: ");
request = urllib.request.Request(url1);
response = urllib.request.urlopen(request);
raw_file = response.read().decode('utf-8');
API_key = re.findall(r"StreamUrl\":\"(.*?),\"",raw_file);
#print API_key;
#print "The API key is: " + API_key[0];
request2 = urllib.request.Request(str(API_key[0]));
response2 = urllib.request.urlopen(request2);
key_content = response2.read().decode('utf-8');
raw_stream_url = re.findall(r"Url\": \"(.*?)\"",key_content);
bandwidth = re.findall(r"Bandwidth\":(.*?),", key_content);
reliability = re.findall(r"lity\":(.*?),", key_content);
isPlaylist = re.findall(r"HasPlaylist\":(.*?),",key_content);
codec = re.findall(r"MediaType\": \"(.*?)\",", key_content);
tipe = re.findall(r"Type\": \"(.*?)\"", key_content);
total = 0
for element in raw_stream_url:
total = total + 1
i = 0
print ("I found " + str(total) + " streams.");
for element in raw_stream_url:
print ("Stream #" + str(i + 1));
print ("Stream stats:");
print ("Bandwidth: " + str(bandwidth[i]) + " kilobytes per second.");
print ("Reliability: " + str(reliability[i]) + "%");
print ("HasPlaylist: " + str(isPlaylist[i]));
print ("Stream codec: " + str(codec[i]));
print ("This audio stream is " + tipe[i].lower());
print ("Pure streaming URL: " + str(raw_stream_url[i]));
i = i + 1
input("Press enter to close")
Shahar的回答真的很有帮助, 但我发现自己做这些事情很繁琐, 所以我做了一个小小的Python程序:
import re
import urllib2
import string
url1 = raw_input("Please enter a URL from Tunein Radio: ");
open_file = urllib2.urlopen(url1);
raw_file = open_file.read();
API_key = re.findall(r"StreamUrl\":\"(.*?),",raw_file);
#print API_key;
#print "The API key is: " + API_key[0];
use_key = urllib2.urlopen(str(API_key[0]));
key_content = use_key.read();
raw_stream_url = re.findall(r"Url\": \"(.*?)\"",key_content);
bandwidth = re.findall(r"Bandwidth\":(.*?),", key_content);
reliability = re.findall(r"lity\":(.*?),", key_content);
isPlaylist = re.findall(r"HasPlaylist\":(.*?),",key_content);
codec = re.findall(r"MediaType\": \"(.*?)\",", key_content);
tipe = re.findall(r"Type\": \"(.*?)\"", key_content);
total = 0
for element in raw_stream_url:
total = total + 1
i = 0
print "I found " + str(total) + " streams.";
for element in raw_stream_url:
print "Stream #" + str(i + 1);
print "Stream stats:";
print "Bandwidth: " + str(bandwidth[i]) + " kilobytes per second."
print "Reliability: " + str(reliability[i]) + "%"
print "HasPlaylist: " + str(isPlaylist[i]) + "."
print "Stream codec: " + str(codec[i]) + "."
print "This audio stream is " + tipe[i].lower() + "."
print "Pure streaming URL: " + str(raw_stream_url[i]) + ".";
i = i + 1
raw_input("Press enter to close TMUS.")
基本上就是把沙哈尔的解决方案自动化了 It's basically Shahar's solution automated.
当你进入一个流网址时,你会得到一个文件.把这个文件喂给一个解析器来提取其中的内容.这个文件是(通常)纯文本,包含要播放的网址。