我写了一个代码来分隔偶数和奇数，但我遇到了这个错误？

Question

while True:
    num = input("pls type the number: ")
    
    # check if it's int or string 
    
    number = int(num)  
    except ValueError:
    print("error try again !!")
    continue  # if it was wrong go back
    
    # check if it's even or odd
    if number % 2 == 0:
        result = number * 2
        print("it's even" , number)
        print("The End")
    else:
        result = number + 1
        print("its odd",number)
        print("The End")
    break 

语法错误：语法无效 怎么了？

Answer 1

您的代码有一些问题。这是更正后的版本：

while True:
    num = input("Please type the number: ")
    
    try:
        number = int(num)
    except ValueError:
        print("Error, try again!")
        continue  # Go back if input was not an integer
    
    # Check if it's even or odd
    if number % 2 == 0:
        result = number * 2
        print("It's even", number)
        print("The End")
    else:
        result = number + 1
        print("It's odd", number)
        print("The End")
    
    break  # Exit the loop

主要修复：

1. 缩进：正确缩进

   try

   、

   except

   和其他语句。
2. 异常处理：确保

   try

   和

   except

   放置正确。

3. break

   的使用：将

   break

   移到

   if-else

   块之外，处理后退出循环。 https://topfollow-apk.com/blog/