检查参数是否等于模型定义的常数

Question

在我的MeetingType模型中，我有这个常数：

const EXAMPLE_SHAREHOLDERS_MEETING =
[
    'Shareholders meeting',
    'Management meeting',
    'General meeting',
    'Start meeting'
];

在我的控制器中，我从模型中这样调用一个函数：

$topics = MeetingType::get_meeting_type_topics($meetingTypeName);

$meetingTypeName等于“股东会议”。

如何检查传递的参数是否匹配我的常量数组？这是我正在谈论的功能：

/**
 * Define and return MeetingType Topics. 
 *
 * @param string $meetingTypeName
 * @return array
 */
public static function get_meeting_type_topics($meetingTypeName)
{
    switch (MeetingType::EXAMPLE_SHAREHOLDERS_MEETING) {
        case 'Shareholders meeting':
            $topics = [
                'Opening',
            ];
            break;
        case 'Management meeting':
            $topics = [
                'Aanwezigen / afwezigen',
            ];
            break;
        case 'General meeting':
            $topics = [
                'Opening',
            ];
            break;
        case 'Start meeting':
            $topics = [
                "Uitleg van deze vergadering",
            ];
            break;
    }

    return $topics;
}

Answer 1

我愿意

class MeetingEntity {
// ...
  const SHAREHOLDERS_MEETING = 0;
  const MANAGEMENT_MEETING = 1;
  const GENERAL_MEETING = 2;
  const START_MEETING = 3;

  const MEETINGS_TYPES =
  [
    0 => self::SHAREHOLDERS_MEETING,
    1 => self::MANAGEMENT_MEETING,
    2 => self::GENERAL_MEETING,
    3 => self::START_MEETING,
  ];
// ...

对于有些习惯于这种模式的原因。特别是在键不是数字而是单词的情况下，这非常有用。

比起您可以使用一些简单的开关：

switch($aMeetingType) {
    case MeetingEntity::SHAREHOLDERS_MEETING:
      // ....
      break;

或更安全一些：

if (array_key_exists($aMeetingType, MeetingEntity::MEETING_TYPES)) {
    switch(MeetingEntity::MEETING_TYPES[$aMeetingType]) {
        case MeetingEntity::SHAREHOLDERS_MEETING:
            // ...
            break;
    }
} else { // throw

Answer 2

您可以将const EXAMPLE_SHAREHOLDERS_MEETING重新定义为

const EXAMPLE_SHAREHOLDERS_MEETING =
[
    'Shareholders meeting' => 'Opening',
    'Management meeting' => 'Aanwezigen / afwezigen',
    'General meeting' => 'Opening',
    'Start meeting' => "Uitleg van deze vergadering",
];

并且在您的函数中返回类似：

public static function get_meeting_type_topics($meetingTypeName)
{
    return MeetingType::EXAMPLE_SHAREHOLDERS_MEETING[$meetingTypeName];
}